# 针对新高考中选做题的新模式：1道题包含2个小题（填空题+解答题），
#                   需要将这俩个小题单独拆分出来，题号用，例如12-1或12(1)


import re


def toslave_aft(one_item):
    """
    将一道题拆分为俩道题
    :param one_item: 已经按题号结构化好的单道题目
    :return:
    """
    # th1 = {"(Ⅰ)": "(1)", "(Ⅱ)": "(2)", "(Ⅲ)": "(3)", "(IV)": "(4)", "(Ⅳ)": "(4)", "(Ⅴ)": "(5)",
    #        "Ⅰ": "(1)", "Ⅱ": "(2)", "Ⅲ": "(3)", "IV": "(4)", "Ⅳ": "(4)", "Ⅴ": "(5)"}
    # con = re.sub(r"([\n】])\s*[(（]\s*(" + "|".join(th1.keys()) + ")\s*[)）]", lambda x: x.group(1) + th1[x.group(2)], con)
    # parse = re.sub(r"([\n】])\s*[(（]\s*(" + "|".join(th1.keys()) + ")\s*[)）]", lambda x: x.group(1) + th1[x.group(2)],
    #                parse)
    if "is_optional" not in one_item or one_item["is_optional"] != 'true':
        return one_item

    con, ans, parse = one_item["stem"], one_item["key"], one_item["analysis"]
    con = re.sub("(<[/a-z]+>|[(（]\s*\d+\s*分\s*[）)])\s*([(（]\s*\d\s*[）)])", r"\1" + "<br/>" + r"\2", con)
    parse = re.sub("(<[/a-z]+>)\s*([(（]\s*\d\s*[）)])", r"\1" + "<br/>" + r"\2", parse)
    parse = re.sub(r"^\s*(【解[答析]】|解[答析]\s*[:：])", "", parse)
    parse = re.sub(r"<br/>\s*((<img src=.*?[/\"]>\s*)+)\s*([(（]\s*[12]\s*[)）])", r"<br/>\1<br/>\3", parse)
    # parse = re.sub("(答案分?别?[为是]?\s*[：:])\s*[(（]\s*(\d)\s*[)）]", r"\1[#[\2]#]", parse)
    con = re.sub(r"<br/>\s*((<img src=.*?[/\"]>\s*)+)\s*([(（]\s*[12]\s*[)）])", r"<br/>\1<br/>\3", con)
    con_list = re.split(r"(?<=<br/>)\s*[(（]\s*[12]\s*[)）]", "<br/>" + con)
    # print(con_list)
    def sub1(ss):
        return "（1）" + ss.group(1).replace(" ", "") + " （2）"
    ans = re.sub("[(（]\s*1\s*[)）]\s*(([A-G]\s*)+)\s*[(（]\s*2\s*[)）]",
                 sub1, ans)
    ans_list = re.split("（1）\s*([A-G]+)\s*（2）", ans)
    if len(con_list)==3:
        con_list = con_list[1:]
        if ans == "见解析" or len(ans_list)<=2 or len(ans_list)>3:
            ans_list = ["见解析"]*2
        else:
            ans_list = ans_list[1:]

        # 解析
        if parse != "略":
            parse_list = re.split("(?<=<br/>)\s*[(（]\s*[12]\s*[)）]", "<br/>" + parse)
            if len(parse_list)==3:
                parse_list = parse_list[1:]
                all_slave = []
                for n in range(2):
                    # if "blank_num" in one_item:
                    #     type = "填空题"
                    one_slave = {"stem": con_list[n].replace("<br/>", "\n").strip().replace("\n", "<br/>"),
                         "key": ans_list[n].replace("<br/>", "\n").strip().replace("\n", "<br/>"),
                         "analysis": parse_list[n].replace("<br/>", "\n").strip().replace("\n", "<br/>"),
                         "type": "填空题" if not n else "解答题",
                         "item_id": str(one_item['item_id']) + "-" + str(n+1)
                     }
                    all_slave.append(one_slave)
                one_item["slave"] = all_slave
                del one_item['stem'], one_item['key'], one_item['analysis']
            else:
                if one_item['text_errmsgs']:
                    one_item['text_errmsgs'] += ";"
                one_item['text_errmsgs'] += "本选做题的两小题格式不正确，请将每小题答案换行处理"
    else:
        if one_item['text_errmsgs']:
            one_item['text_errmsgs'] += ";"
        one_item['text_errmsgs'] += "本选做题的两小题格式不正确，请将每小题题干换行处理"
    # print(one_item)
    return one_item


def toslave_bef(one_item):
    """
    将一道题拆分为俩道题
    :param one_item: 已经按题号结构化好的单道题目
    :return:
    """
    # th1 = {"(Ⅰ)": "(1)", "(Ⅱ)": "(2)", "(Ⅲ)": "(3)", "(IV)": "(4)", "(Ⅳ)": "(4)", "(Ⅴ)": "(5)",
    #        "Ⅰ": "(1)", "Ⅱ": "(2)", "Ⅲ": "(3)", "IV": "(4)", "Ⅳ": "(4)", "Ⅴ": "(5)"}
    # con = re.sub(r"([\n】])\s*[(（]\s*(" + "|".join(th1.keys()) + ")\s*[)）]", lambda x: x.group(1) + th1[x.group(2)], con)
    # parse = re.sub(r"([\n】])\s*[(（]\s*(" + "|".join(th1.keys()) + ")\s*[)）]", lambda x: x.group(1) + th1[x.group(2)],
    #                parse)
    # print(one_item)
    con, ans, parse = one_item["stem"], one_item["key"], one_item["parse"]
    con = re.sub("(<[/a-z]+>|[(（]\s*\d+\s*分\s*[）)])\s*([(（]\s*\d\s*[）)])", r"\1" + "\n" + r"\2", con)
    con = re.sub(r"\n\s*((<img src=.*?[/\"]>\s*)+)\s*([(（]\s*[123]\s*[)）])", r"\n\1\n\3", con, flags=re.S)
    # con_list = re.split(r"(?<=\n)\s*[(（]\s*[123]\s*[)）]", "\n" + con)
    # print(con_list)
    parse = re.sub("(<[/a-z]+>|[(（]\s*\d+\s*分\s*[）)])\s*([(（]\s*\d\s*[）)])", r"\1\n\2", parse)
    parse = re.sub(r"^\s*(【解[答析]】|解[答析]\s*[:：])", "", parse)
    parse = re.sub(r"\n\s*((<img src=.*?[/\"]>\s*)+)\s*([(（]\s*[123]\s*[)）])", r"\n\1\n\3", parse)
    # parse = re.sub("(答案分?别?[为是]?\s*[：:])\s*[(（]\s*(\d)\s*[)）]", r"\1[#[\2]#]", parse)

    # 默认第一题是选择形式的填空题！！！！！
    def sub1(ss):
        if int(ss.group(1)) in [1, 2] and int(ss.group(4)) - int(ss.group(1)) == 1:
            return "（{}）".format(ss.group(1)) + ss.group(2).replace(" ", "") + "\n" + " （{}）".format(ss.group(4))
        else:
            return ss
    ans = re.sub("[(（]\s*(\d)\s*[)）]\s*(([A-G][、､\s]*)+)\s*[(（]\s*(\d)\s*[)）]", sub1, ans)

    all_slave = []
    true_n = 2
    if re.search(r"(^|\n)[(（]1[)）]|(^|\n)[①②]\s*[(（].*?(选[修学]|[学考]生).*?[)）]", con):
        con_list = re.split("\n[(（][123][)）]", "\n"+con)
        if len(con_list) < 2:
            con_list = re.split("\n[①②③]\s*[(（].*?[选修学考生].*?[)）]", "\n" + con)
        if re.search(r"\n[(（]3[)）]", con):
            if len(con_list)-1 != 3:
                text_errmsgs = "本选做题的小题格式不正确，请将每小题题干换行处理"
                one_item['errmsgs'].append(text_errmsgs)  # if one_item['errmsgs'] else text_errmsgs
                return one_item
            else:
                true_n = 3
        elif len(con_list)-1 != 2:
            text_errmsgs = "本选做题的小题格式不正确，请将每小题题干换行处理"
            # one_item['errmsgs'] += ";" + text_errmsgs if one_item['errmsgs'] else text_errmsgs
            one_item['errmsgs'].append(text_errmsgs)
            return one_item
        con_list = con_list[1:]

        # if len(con_list)-1 == true_n:
        #     con_list = con_list[1:]
        ans_list = re.split("\n[(（][123][)）]", "\n" + ans)
        if "#" in ans:
            ans_list = ans.split("#")
        else:
            if ans == "见解析" or (true_n ==2 and (len(ans_list)<=2 or len(ans_list)>3))\
                    or (true_n ==3 and (len(ans_list)<=3 or len(ans_list)>4)):
                ans_list = ["见解析"]*true_n
            else:
                ans_list = ans_list[1:]

        # 解析
        if parse and parse != "略":
            parse_list = re.split("(?<=\n)\s*[(（]\s*[12]\s*[)）]", "\n" + parse, maxsplit=2)
            if true_n == 3:
                parse_list = re.split("(?<=\n)\s*[(（]\s*[123]\s*[)）]", "\n" + parse, maxsplit=3)
            if len(parse_list) == true_n+1:
                parse_list = parse_list[1:]
                for n in range(true_n):
                    item_type = _type_judge(con_list[n], ans_list[n])    # 题型判断
                    one_slave = {"stem": con_list[n].strip(),
                                 "key": ans_list[n].strip(),
                                 "parse": parse_list[n].strip(),
                                 "type": item_type,
                                 "item_id": str(one_item['item_id']) + "-" + str(n+1),
                                 # "score": 0.0,
                                 "errmsgs": []
                                 }
                    all_slave.append(one_slave)
            else:
                if ans_list == ["见解析"]*true_n:
                    one_item["errmsgs"].append("本选做题的小题格式不正确，请将每小题答案和解析换行处理")
                else:
                    one_item["errmsgs"].append("本选做题的小题格式不正确，请将每小题的解析换行处理")
                return one_item
        else:
            errmsgs = ["本题缺少解析"]
            if ans_list == ["见解析"]*true_n:
                errmsgs.append("本选做题缺少答案或答案格式不正确，请将每小题答案换行处理")
            for n in range(true_n):
                item_type = _type_judge(con_list[n], ans_list[n])
                one_slave = {"stem": con_list[n].strip(),
                             "key": ans_list[n].strip() if ans_list[n]!="见解析" else "",
                             "parse": "",
                             "type": item_type,
                             "item_id": str(one_item['item_id']) + "-" + str(n + 1),
                             "score": 0.0,
                             "errmsgs": errmsgs
                             }

                all_slave.append(one_slave)
    else:
        text_errmsgs = "本选做题的小题格式不正确，请将第1小题的题干换行处理"
        one_item['errmsgs'].append(text_errmsgs)
        return one_item

    return all_slave


def _type_judge(con, ans):
    """
    # 题型判断
    :return:
    """
    item_type = "解答题"
    b1 = re.search(r"选择?对[1一2两3三]个", con)
    con0 = re.sub("([A-H]\s*[.．、､])+", "A、", "\n" + con)
    b21 = len(re.findall(r"[\n\s]\s*[A-H]\s*[.．、､]", con0)) >= 3
    b22 = len(re.findall(r"[\n\s]\s*[A-H]\s*[.．、､]", con0)) >= 5
    b31 = re.match(r"[A-H][A-H;；和与、､\s]*?$", ans.strip())
    b32 = re.match(r"[A-H][;；和与、､\s][A-H][A-H;；和与、､\s]*?$", ans.strip())

    if b1 or b22 or b32:
        item_type = "多选题"
    elif b31 or b21:
        item_type = "单选题"
    elif re.findall(r"_{2,}", ans.strip()):
        item_type = "填空题"

    return item_type


if __name__ == '__main__':
    def sub1(ss):
        return "（1）" + ss.group(1).replace(" ", "") + "（2）"
    ans = "答案：(1)B C E　(2)(ⅰ)T0　(ⅱ)"
    ans = re.sub("[(（]\s*1\s*[)）]\s*(([A-G]\s*)+)\s*[(（]\s*2\s*[)）]",
                 sub1, ans)
    print(ans)