# -*- coding: utf-8 -*-
import re
from pprint import pprint

from pyquery import PyQuery as pq


#
# pattern = re.compile(r"\[来源.*?\]|www\..*?com")
#
# filter_words = ["学科网", "高考资源网", "Ziyuanku.com", "WWW.ziyuanku.com",
#                 "高☆考♂资♀源€网", "w.w.w.k.s.5.u.c.o.m", "本资料由《七彩教育网》www.7caiedu.cn 提供!",
#                 "本资料来源于《七彩教育网》http://www.7caiedu.cn", "本资料由《七彩教育网》www.7caiedu.cn 提",
#                 "高考试题来源:"]
#
#
# def filter_word(txt_list):
#     new_txt_list = []
#     for word in txt_list:
#         if not word.strip():
#             continue
#         new_word = re.sub(pattern, "", word)
#         for keys in filter_words:
#             if keys in new_word:
#                 new_word = new_word.replace(keys, "")
#         new_txt_list.append(new_word)
#     return new_txt_list


def filter_data(x):
    if not str(x).replace(" ", "").strip():
        pass
    else:
        return str(x)


def replace_k(con):
    # con = str(con).replace(" ", "+")
    # con = str(con).replace(" ", "+")
    con = re.sub(r'\s(?!(src="http|_src="http|class="tiankong"|data-num=))', "#+#", str(con))
    return pq(con, parser="html")


def css_label_wash(content):
    # todo add 9-4
    """
    清洗文本中带有的css标签
    :param content:
    :return:
    """
    # temp_con = re.sub('</?p(\s*|\s+style=.*?")?>', "", str(content))
    if re.search('</?(span|font|article|ul|ol|div)(\s*|\s+style=.*?")>|text\s*-\s*decoration: underline|border\s*-\s*bottom:', str(content)) is None:
        # content = re.sub('</p\s*>', "\n", content).strip().replace("\n\n", "\n").replace("\n", "<br/>")
        def subp(s):
            cons = s.group(1)
            if '<p style="text-indent:' in cons or '<p style="text-align:' in cons:
                return cons
            else:
                return "<p>"
        content = re.sub('(<p(\s*|\s+style=.*?")>)', subp, content)
        content = re.sub('</p><p>', "</p>\n<p>", content)
        return content
    else:
        content = re.sub(r'<font\s+style="color: red">', "", str(content))
        content = re.sub(r'<span\s+style="color: red">', "", str(content))
        content = re.sub(r'<span\s+style="color: blue">', "", str(content))
        content = re.sub(r'<font\s+style="color: blue">', "", str(content))
        content = content.replace("</font >", "").replace("</font>", "")
        # content = content.replace("</span >", "").replace("</span>", "")
        content = content.replace('<p style="height: 0;">&nbsp;</p>', "\n").replace('<p><br/></p>', "\n")
        content = content.replace("</p>", "</p>\n")
        # content = re.sub('<p( style=.*?")?>', "", content)
        # content = re.sub('<br\s*/?>', "\n", content)
        # parm = False
        # if "<article>" not in str(content):
        #     parm = True
        subs2img = {}
        if re.search('<img.*? src="', content) or "</table>" in content:
            all_imgs = re.findall('<img.*? src=.*?[\s/"]>|<table.*?>.*?</table>',
                                  content, flags=re.S)
            for k, img in enumerate(all_imgs):
                content = content.replace(img, "&{}&".format(k))
                subs2img["&{}&".format(k)] = img
        content = re.sub(r"<(su[bp])>(.*?)</(su[bp])>", r"【\1】\2【/\3】", content)

        html = pq(content, parser="html")
        a = []

        if html.children():
            # temph = [str(i) for i in html.children().items()]
            for line in html.children().items():  # <p>.*?</p>里面的内容可能会被过滤掉
                test = str(line)  # line.text()
                # 保留下划线及着重符标签   <span style="text-decoration: underline;">
                # 波浪线：<span style="text-decoration: underline wavy;">
                # pq会将多个空格换成一个
                # print(str(line))
                if '<span style="text-decoration: underline' in str(line) or '<span class="dots"' in str(line)\
                        or re.search('<(p|div)( class="[a-z\-]+")? style="text-indent:'
                                     '|<(p|div)( class="[a-z\-]+")? style="text-align:|<strong>|<em>', str(line)):
                    line = re.sub(r'<span style="text-decoration: underline(.*?">.+?)</span>', r"【1#\1##】", str(line))
                    line = re.sub(r'<span class="dots">(.+?)</span>', r"【2#\1##】", str(line))
                    line = re.sub(r'<(p style="text-(indent|align):.*?">.+?)</p>', r"【\1##3】", str(line))
                    line = re.sub(r'<div( class="[a-z\-]+")?( style="text-(indent|align):.*?")( [a-z\d\-"=]+")?(>.+?)</div>',
                                  r"【div\2\5##3】", str(line), flags=re.S)
                    # line = re.sub(r'<(strong|em)>(.+?)</\1>', r"【\1##\2##\1】", str(line))
                    # 分开处理会比较好，嵌套的格式也能全处理
                    line = re.sub(r'<strong>(.+?)</strong>', r"【strong##\1##strong】", str(line))
                    line = re.sub(r'<em>(.+?)</em>', r"【em##\1##em】", str(line))
                    # print(line)
                    line = line.replace(" ", "【+】")
                    line = pq(line)
                    new_line = list(map(lambda x: str(x).replace("【1#", '<span style="text-decoration: underline')
                                        .replace("##】", "</span>").replace("【2#", '<span class="dots">')
                                        .replace("【p【+】style=", "<p style=").replace("【div【+】style=", "<p style=")
                                        .replace("【div【+】class=", "<p class=")
                                        .replace("##3】", "</p>").replace("【strong##", "<strong>").replace("【em##", "<em>")
                                        .replace("##strong】", "</strong>").replace("##em】", "</em>").replace("【+】", " "),
                                        line.text().split("\n")))
                    a.extend(new_line)
                elif str(line).startswith("<p") and line.text().strip():
                    if '<img src="http://' in str(line) or "text-decoration: underline" in str(line) or "border-bottom:" in str(line) or "text - decoration: underline" in str(line):
                        # a.append(line.html().replace("<br />", "\n").replace("<br/>", "\n").replace("<br>", "\n") + "\n")
                        a.append(line.html())
                    else:
                        line = replace_k(line)
                        if re.search(r"\n|<br\s*/?>", str(line), flags=re.S):
                            line = re.sub(r"\n|<br\s*/?>", "#*#", str(line), flags=re.S)
                            line = pq(line)
                            new_line = list(map(lambda x: str(x).replace("#+#", " "), line.text().split("#*#")))
                            a.extend(new_line)
                        else:
                            if line.text().strip():
                                a.append(line.text().replace("#+#", " "))

                elif "<article>" in str(line) and "</article>" in str(line):
                    line = re.sub(r'<p.*?>', "", str(line.html()))
                    b = line.replace('</p>', ""). \
                        replace("<br>", "\n"). \
                        replace("<br/>", "\n"). \
                        replace("<br />", "\n"). \
                        replace('<p style="height: 0;">&nbsp;</p>', "\n"). \
                        replace('<p style="height: 0;"> </p>', "\n")
                    b_list = b.split("\n")
                    # b_list = list(filter(lambda x: str(x), b_list))
                    b_list = list(filter(filter_data, b_list))
                    b_list = list(map(lambda x: str(x), b_list))
                    a.extend(b_list)

                elif str(line).startswith("<ul"):
                    a.append(line.text())
                elif line.attr("class") == "slave-datas":
                    for j, ss in enumerate(line.children().items()):
                        if ss(".read-list-title").text():
                            a.append(str(j + 1) + "." + ss(".read-list-title").text())
                        if ss(".read-list-opt").text():
                            a.append(ss(".read-list-opt").text().replace("\n", "\t"))
                        if str(ss).startswith("<ul"):
                            a.append(ss.text())
                elif str(line).startswith("<table"):
                    a.append(str(line))
                elif str(line).startswith("<ol"):
                    for i, ss in enumerate(line.children().items()):
                        a.append(str(i + 1) + "." + ss.text())
                elif str(line).startswith("<br>") or str(line).startswith("<br/>"):
                    a.append(str(line))
                else:
                    # print('test:',line.text())  # 自动去掉了图片
                    if line.text().strip():
                        line = replace_k(line)
                        # a.append(line.text().replace("+", "\xa0") + "\n")
                        a.append(line.text().replace("#+#", " "))

        else:
            # if html.text().strip():  把换行\n 都去掉了
            #     a.append(html.text())
            # a.append(str(html)) # 会自动带上</?p> ；&变为&amp；
            a.append(content.strip())

        new_a = "\n".join(list(map(lambda x: x.strip(), a)))
        if subs2img:
            new_a = re.sub("|".join(subs2img.keys()), lambda x: subs2img[x.group()], new_a)
        # new_a = "<p>" + new_a.replace("\n\n", "\n").replace("\n", "</p>\n<p>") + "</p>"
        new_a = re.sub("(?<!</p>)\s*\n", "<br/>",  new_a.replace("\n\n", "\n"))  # 2024.6.13
        new_a = re.sub("<br/>(\n|<br/>)+", "<br/>", new_a)
        new_a = "<p>" + new_a + "</p>"
        new_a = re.sub(r'<p>(<p (class|style)=.+?)</p>$', r"\1", new_a, flags=re.S)
        # for sb, img in subs2img.items():  # 2021
        #     new_a = new_a.replace(sb, img)
        # if parm:
        #     new_a[0] = "\xa0" * 4 + new_a[0]
        new_a = re.sub(r"【(/?su[bp])】", r"<\1>", new_a)
        return new_a


def again_parse(content):
    # todo add 9-4
    content = re.sub(r'<font\s+style="color: red">', "", str(content))
    content = re.sub(r'<span\s+style="color: red">', "", str(content))
    content = re.sub(r'<span\s+style="color: blue">', "", str(content))
    content = re.sub(r'<font\s+style="color: blue">', "", str(content))
    content = str(content).replace("</font >", "").replace("</font>", "")
    content = str(content).replace("</span >", "").replace("</span>", "")
    content = str(content).replace('<p style="height: 0;">&nbsp;</p>', "\n").replace('<p><br/></p>', "\n")
    # parm = False
    # if "<article>" not in str(content):
    #     parm = True

    html = pq(content, parser="html")
    a = []
    if html.children():
        for line in html.children().items():

            if (str(line).startswith("<p") and line.text().strip()) or "http://zxhx-1302712961.cos.ap" in str(line):

                if 'http://zsytk2.zhixinhuixue.com/static/images' in str(line) \
                        or "text-decoration: underline" in str(line) \
                        or "border-bottom:" in str(line) \
                        or "text - decoration: underline" in str(line) \
                        or 'http://zxhx-1302712961.cos.ap' in str(line):
                    a.append(line.html().replace("<br />", "\n").replace("<br/>", "\n").replace("<br>", "\n") + "\n")
                else:
                    line = replace_k(line)
                    if "<br>" in str(line) or "<br/>" in str(line) or "<br />" in str(line):
                        line = str(line).replace("<br/>", "###").replace("<br>", "###").replace("<br />", "###")
                        line = pq(line)
                        new_line = list(map(lambda x: str(x).replace("+", "\xa0") + "\n", line.text().split("###")))
                        a.extend(new_line)
                    else:
                        if line.text().strip():
                            a.append(line.text().replace("+", "\xa0") + "\n")

            elif "<article>" in str(line) and "</article>" in str(line):
                line = re.sub(r'<p.*?>', "", str(line.html()))
                b = line.replace('</p>', ""). \
                    replace("<br>", "\n"). \
                    replace("<br/>", "\n"). \
                    replace("<br />", "\n"). \
                    replace('<p style="height: 0;">&nbsp;</p>', "\n"). \
                    replace('<p style="height: 0;"> </p>', "\n")
                b_list = b.split("\n")
                # b_list = list(filter(lambda x: str(x), b_list))
                b_list = list(filter(filter_data, b_list))
                b_list = list(map(lambda x: str(x) + "\n", b_list))
                a.extend(b_list)

            elif str(line).startswith("<ul"):
                a.append(line.text() + "\n")
            elif line.attr("class") == "slave-datas":
                for j, ss in enumerate(line.children().items()):
                    if ss(".read-list-title").text():
                        a.append(str(j + 1) + "." + ss(".read-list-title").text() + "\n")
                    if ss(".read-list-opt").text():
                        a.append(ss(".read-list-opt").text().replace("\n", "\t") + "\n")
                    if str(ss).startswith("<ul"):
                        a.append(ss.text() + "\n")
            elif str(line).startswith("<table"):
                a.append(str(line) + "\n")
            elif str(line).startswith("<ol"):
                for i, ss in enumerate(line.children().items()):
                    a.append(str(i + 1) + "." + ss.text() + "\n")
            else:
                if line.text().strip():
                    line = replace_k(line)
                    a.append(line.text().replace("+", "\xa0") + "\n")
    else:
        if html.text().strip():
            a.append(html.text() + "\n")
    a = "\n".join(a).split("\n")
    new_a = list(filter(lambda x: x.strip(), a))
    # if parm:
    #     new_a[0] = "\xa0" * 4 + new_a[0]
    return new_a


if __name__ == '__main__':
    cons = r'''
       <div class="stem-wraper" data-v-494b33d9=""><span class="stem" data-v-494b33d9="">下述有关功和能量说法正确的是（ ）</span></div>
<ul class="stem-options" data-v-494b33d9="">
<li data-v-494b33d9=""><span class="analysis-prefix" data-v-494b33d9="">A.</span><span data-v-494b33d9="">物体做功越多，<span style="text-decoration: underline wavy;">物体的能量就越大</span></span></li>
<li data-v-494b33d9=""><span class="analysis-prefix" data-v-494b33d9="">B.</span><span data-v-494b33d9="">摩擦力可能对物体做正功，也可能做负功，<span style="text-decoration: underline;">也可以不做功</span></span></li>
<li data-v-494b33d9=""><span class="analysis-prefix" data-v-494b33d9="">C.</span><span data-v-494b33d9="">能量耗散表明，能量守恒定律有些情况下并不成立</span></li>
<li data-v-494b33d9=""><span class="analysis-prefix" data-v-494b33d9="">D.</span><span data-v-494b33d9="">弹簧拉伸时的弹性势能一定大于压缩时的弹性势能</span></li>
</ul>
<div class="topic-analysis" data-v-494b33d9="">
<div class="topic-analysis-content" data-v-494b33d9=""><span class="analysis-prefix" data-v-494b33d9="">【答案】</span><span data-v-494b33d9="">B</span></div>
<div class="topic-analysis-content" data-v-494b33d9=""><span class="analysis-prefix" data-v-494b33d9="">【解析】</span><span data-v-494b33d9="">功是能量转化的量度，物体做功越多，物体的能量转化就越多，而不是能量越大。故A错误；摩擦力方向可能与物体运动方向相同、也与物体运动方向相反，所以摩擦力可能对物体做正功，也可能做负功。物体也可能没有位移，摩擦力不做功，故B正确；能量耗散虽然不会使能的总量减少，但能量的可利用率越来越低，即能量的品质越来越低；根据能量守恒定律可知，虽然能量的可利用率越来越低，但能量总和保持不变，仍然遵守能量守恒定律，故C错误；弹簧的弹性势能与形变量有关，弹簧拉伸时与压缩时弹性势能可能相等，也可能拉伸时的弹性势能小于压缩时的弹性势能。故D错误。故选B。</span></div>
</div>
    '''
#     cons = '''<p style="margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;text-align:justify;text-justify:inter-ideograph;line-height:150%"><span style="line-height: 150%;font-size: 14px">Unbelievable</span><span style=";font-family:宋体;line-height:150%;font-size:14px"><span style="font-family:宋体">！</span></span><span style="line-height: 150%;font-size: 14px">Oh..., _____ you don&#39;t mind, I&#39;ll stop and take a deep breath.</span></p><p><br/></p>
# <p>【答案】<p style="margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;text-align:justify;text-justify:inter-ideograph;line-height:150%"><span style=";font-family:宋体;line-height:150%;font-size:14px">1</span><span style="line-height: 150%;font-size: 14px">.if</span><span style=";font-family:宋体;line-height:150%;font-size:14px"><span style="font-family:宋体">。考查</span></span><span style="line-height: 150%;font-size: 14px">if</span><span style=";font-family:宋体;line-height:150%;font-size:14px"><span style="font-family:宋体">引导的条件状语从句。根据句意可知。</span></span></p><p><br/></p></p>
# <p>【解析】</p>'''

    # pprint(cons)
    # print(again_parse(cons))
    # print(again_parse(cons))
    # print(list(map(lambda x: str(x).replace("     ", " "), again_parse(cons))))
    # con1 = r'<p>解：A．研究跨栏动作时，刘翔的大小和形状不能忽略，不能看作质点，故A错误；<br/>B．选取不同的参考系，物体的运动状态是不相同的，故B错误；<br/>C．出租车收费是按路程收费的，故C错误；<br/>D．第<img src="http://192.168.1.145:10811/static/physical_formulas_imgs/16184553930794225.png" data-latex="${4 \rm{s} }$" width="13",height="11" />是指<img src="http://192.168.1.145:10811/static/physical_formulas_imgs/16184553931930702.png" data-latex="${1 \rm{s} }$" width="12",height="11" />的时间，是指从<img src="http://192.168.1.145:10811/static/physical_formulas_imgs/16184553930220437.png" data-latex="${3 \rm{s} }$" width="13",height="11" />末到<img src="http://192.168.1.145:10811/static/physical_formulas_imgs/16184553930794225.png" data-latex="${4 \rm{s} }$" width="13",height="11" />末这一段时间，故D正确；<br/>故选：D．</p>'

    cons1 = """
    <div class="stem-wraper" data-v-00256703="">
<p>阅读下面这首宋诗，完成下列小题。（本题共2小题，9分）</p>
<p style="text-align: center;"><span style="font-family: 楷体;">除夜野宿常州城外二首（其二）</span></p>
<p style="text-align: center;"><span style="font-family: 楷体;">苏轼</span></p>
<p style="text-align: center;"><span style="font-family: 楷体;">南来三见岁云徂<sup>①</sup>，直恐终身走道途。</span></p>
<p style="text-align: center;"><span style="font-family: 楷体;">老去怕看新历日，退归拟学旧桃符。</span></p>
<p style="text-align: center;"><span style="font-family: 楷体;">烟花已作青春<sup>②</sup>意，霜雪偏寻病客须。</span></p>
<p style="text-align: center;"><span style="font-family: 楷体;">但把穷愁博长健，不辞最后饮屠苏<sup>③</sup>。</span></p>
<p>【注】①苏轼于熙宁四年(1071)冬到杭州任通判，至作此诗，已度过三个除夕。岁云徂，谓年岁辞去。徂，往。②青春：春季。③古俗，正月初一家人先幼后长依次饮屠苏酒。《时镜新书》晋董勋云：“正旦饮酒先从小者，何也？勋曰：‘俗以小者得岁，故先酒贺之，老者失时，故后饮酒。’”</p>
</div>
<div class="slave" data-v-00256703="">
<div class="slave-item" data-v-00256703="">
<div class="content" data-v-00256703=""><span class="analysis-prefix" data-v-00256703="">14</span><span data-v-00256703="">.</span><span data-v-00256703="">下列对这首诗的理解和赏析，不正确的一项是（ ）</span></div>
<ul class="stem-options" data-v-00256703="">
<li data-v-00256703=""><span class="analysis-prefix" data-v-00256703="">A.</span><span data-v-00256703="">诗人离开朝廷南来已三年，恐怕自己终身奔走于宦途而不能践偿其政治抱负。</span></li>
<li data-v-00256703=""><span class="analysis-prefix" data-v-00256703="">B.</span><span data-v-00256703="">因桃符一年一换，诗人自比“桃符”，寄托了自己在新的一年仕途晋升的愿望。</span></li>
<li data-v-00256703=""><span class="analysis-prefix" data-v-00256703="">C.</span><span data-v-00256703="">颈联对仗工整，诗人以自然界万物复苏的繁丽景象来反衬出自己的衰病老迈。</span></li>
<li data-v-00256703=""><span class="analysis-prefix" data-v-00256703="">D.</span><span data-v-00256703="">本诗抒发了除夜感慨，“桃符”“烟花”“屠苏”等意象照应节令，节日氛围浓厚。</span></li>
</ul>
</div>
<div class="slave-item" data-v-00256703="">
<div class="content" data-v-00256703=""><span class="analysis-prefix" data-v-00256703="">15</span><span data-v-00256703="">.</span><span data-v-00256703="">末句“不辞最后饮屠苏”意蕴丰富，请简要分析。</span></div>
</div>
</div>
<div class="topic-analysis" data-v-00256703="">
<div class="topic-analysis-content" data-v-00256703=""><span class="analysis-prefix" data-v-00256703="">【答案】</span><span data-v-00256703=""><br><span class="analysis-prefix">14.</span>&nbsp;&nbsp;B<br><span class="analysis-prefix">15.</span>&nbsp;&nbsp;①饮屠苏酒的顺序是自少至老，诗人说“最后饮”，表明了他年事已高。②诗人“辞”掉的是富贵荣华，表明他不再以仕途不畅为意。③“不辞最后饮”又表明他不以岁月流逝为意，以豁达乐观待之，表现了诗人豪放旷达的情怀。<br></span></div>
<div class="topic-analysis-content" data-v-00256703=""><span class="analysis-prefix" data-v-00256703="">【解析】</span><span data-v-00256703=""><br><span class="analysis-prefix">14.</span>&nbsp;&nbsp;本题考查学生鉴赏诗歌的形象、表达技巧和情感的能力。B.“寄托了自己在新的一年仕途晋升的愿望”曲解文意。由“退归”可知，本句暗指诗人要抛却不如意的仕途，含有退隐之意。故选B。<br><span class="analysis-prefix">15.</span>&nbsp;&nbsp;本题考查学生理解诗句意蕴的能力。诗人一扫前面的郁闷，表示要用“穷”和“愁”换取长久的健康，要屠苏酒来迎新年。正月初一饮屠苏酒是一种习俗，饮用的顺序是自少至老，诗人说“最后饮”，表明了他年事已高。“烟花”二句，以自然界万物复苏的繁丽景象，反衬自己的衰病老迈。“拟学旧桃符”暗指诗人要抛却不如意的仕途，诗人“辞”掉的是富贵荣华，表明他不再以仕途不畅为意。诗人说“不辞最后饮”，不怕轮到我最后一个把屠苏酒饮，表明他不以岁月流逝为意，以豁达乐观待之，以此观照开篇，更见苏轼豪放旷达的情怀。<br></span></div>
</div>
    """
    conss = css_label_wash(cons1)

    print(conss)