new_tiku_structure_v3_sci/utils/ruku_opera.py

# -*- coding:utf-8 -*-

import random, hashlib
import requests
import configs
import shutil
from utils.diffi_label import get_item_diff
from utils.img2latex import get_ocrlatex_by_url
from utils.qcloud_bucket import upload_img_to_qcloud, img_inbucket_count, client, filestream_upload
from concurrent.futures import ProcessPoolExecutor
from concurrent.futures import ThreadPoolExecutor, ProcessPoolExecutor
from utils.image_convert import svg2png
from utils.label_data_Hphy import Label
from bisect import bisect_left
import re, time, os, json, datetime
from copy import deepcopy

logger = configs.myLog(__name__, log_cate="ruku_log").getlog()

subject_id = {
    "高中数学": 3,
    "高中英语": 8,
    "高中物理": 12,
    "高中化学": 13,
    "高中生物": 14,
    "高中政治": 15,
    "高中历史": 16,
    "高中地理": 17,
    "初中数学": 41,
    "初中英语": 42,
    "初中物理": 43,
    "初中化学": 44,
    "初中生物": 45,
    "初中地理": 46,
    "初中政治": 47,
    "初中历史": 48,
    "高中语文": 9,
    "初中语文": 40,
}


class Ruku():
    def __init__(self, items_list, htmlt, svg_data, wordid, callback_info, subject=""):
        self.items_list = items_list
        self.htmlt = htmlt
        self.svg_data = svg_data
        self.wordid = wordid
        self.callback_url = callback_info["callback_url"]
        # self.callback_url = "123456"
        self.source = callback_info["source"]
        self.subject = subject  # items_list[0]["period"] + items_list[0]["subject"]
        self.callback_code = 0
        self.callback_err = ""
        self.ltx2url = {}  # latex 映射 线上可访问url

    def bucket_img_del(self):
        """
        wordbin中图片上传腾讯云的原因：1.存在线上服务器的图片要定期删除，而有的题可能还没审核完；2.上传腾讯云比较便宜
        删除腾讯云中的图片
        根据【解析结果】文本中删除的图片信息，通过阙值判断是否从腾讯云中删除图片
        也有限制：解析结果不能为空，结果中出现的图片在原试卷应该也要有！
        有风险：对于已经校对过的试卷，如果后期有人在资源库里删除了大量文本，很可能导致正在使用的图片被删除
        暂时第三方上传的试卷还是先不要删除比较稳妥！或新建图片用md5命名
        :return:
        """
        items_str = str(self.items_list)
        raw_imgs = []
        # img_source = "" http://zxhx-1302712961.cos.ap-shanghai.myqcloud.com/imgpaper/lqy_upload/612f60307ddb8b2765e50512/img_23.png
        img_source = ""
        items_str = re.sub(r'(<img src=)\'(.*?/(imgpaper/lqy_upload|zyk/uploadfiles/wording)/[^\']*?)\'', r'\1"\2"', items_str)
        if "imgpaper/lqy_upload" in items_str:
            raw_imgs = re.findall(r'<img src=".*?/(imgpaper/lqy_upload/[^"\']*?)"', items_str)  # pdf/图片
            img_source = "p"
        elif "zyk/uploadfiles/wording/" in items_str:
            img_source = "w"  # word
        # elif "stem_img" not in self.items_list[0]:  # 批量解析时没有stem_img字段，但最后前端页面都会补上
        #     img_source = "w"
        # elif any([True if "stem_img" in i and i["stem_img"] else False for i in self.items_list]):
        #     img_source = "p"
        # else:
        #     img_source = "w"
        # pdf/图片解析时，再解析新生成的图片也是用的zyk/uploadfiles/wording/
        logger.info("----【paper_id:{}】本套试卷类型：{}".format(self.wordid, img_source))

        # mj_pic = re.findall(r'<img src=".*?/(zyk/[^"\']+?/MJMATH-\d)', items_str)
        if img_source:
            time1 = time.time()
            raw_imgs.extend(re.findall(r'<img src=".*?/(zyk/uploadfiles/wording/[^"\']*?)"', items_str))
            bucket_imgs = img_inbucket_count(self.wordid, flag=img_source)  # 如果img_source判断错误，则不进行后续操作
            logger.info("----【paper_id:{}】从桶里取数据时间：{}".format(self.wordid, time.time() - time1))
            time2 = time.time()
            if bucket_imgs:
                # 再解析过程中若删除了原已上传到腾讯云上的图片信息，需要判断下是否删除桶中的图片
                # 也有可能出现保存一遍后再保存
                # bucket_imgs = [i['Key'] for i in bucket_imgs]  # dict:[{'Key': put_key}, {}]
                # print("bucket_imgs:", bucket_imgs)
                # print("raw_imgs:", raw_imgs)
                if len(bucket_imgs) - len(raw_imgs) > 5:  # 多余图片超过5张才开始删除，包含mathjax生成的图片
                    bucket_imgs = [i['Key'] for i in bucket_imgs]  # dict:[{'Key': put_key}, {}]
                    to_del_imgs = [bimg for bimg in bucket_imgs if bimg not in raw_imgs]
                    if to_del_imgs:
                        objects = {
                            "Quiet": "true",
                            "Object": [{'Key': item} for item in to_del_imgs]
                        }
                        client.delete_objects(configs.public_bucket, objects)  # 批量删除
                    logger.info("----【paper_id:{}】删除桶数据时间：{}".format(self.wordid, time.time() - time2))

    def mathjx2png(self):
        """
        【基于mathjax渲染输出是svg格式】
        将mathjax渲染的公式转化为图片格式
        mathjax渲染的svg图片提取->保存->格式转化
        :return:
        """
        file_path = configs.IMG_FOLDER + "/" + str(self.wordid)
        svgp_ltx = {}  # svg图片本地路径 映射 latex
        put_key_mjmath = []  # 桶中key
        local_mjmath = []  # 本地图片存储位置
        self.ltx2url = {}  # latex 映射 线上可访问url
        ltx2svgcss = {}  # latex 映射 svg-css
        if self.callback_url and "MathJax" in str(self.svg_data["svg_html_data"]):  # 再解析中存在mathjax公式渲染的标签
            # 需要统计mathjax转png失败时的具体定位  初始思路：based on 索引而展开二分法查找
            # 题号所在位置  topicinfo  topicidx topicno
            # topicinfo = [[nm.end(), nm.group(1)] for nm in re.finditer('class="topic-number">(\d+)\.',
            #                                                            str(self.svg_data["svg_html_data"]))]
            # topicidx = [i[0] for i in topicinfo]
            # topicno = [i[1] for i in topicinfo]
            time3 = time.time()
            all_mathjax = []
            for topic_n, one_svghtml in enumerate(self.svg_data["svg_html_data"]):
                # some_mathjax = [[a.start(), a.group(1)] for a in
                #                 re.finditer('(<span class="MathJax_Preview".*?</script>(</span>)*)', one_svghtml)]
                some_mathjax = [[topic_n+1, a.group(1)] for a in
                                re.finditer('(<span class="MathJax_Preview".*?</script>(</span>)*)', one_svghtml)]
                all_mathjax.extend(some_mathjax)
            # all_mathjax = [[a.start(), a.group(1)] for a in
            #                re.finditer('(<span class="MathJax_Preview".*?</script>(</span>)*)',
            #                             str(self.svg_data["svg_html_data"]))]

            all_linkdata = re.findall('(<path stroke-width=".*?" id="(.*?)" d=".*?"></path>)', self.svg_data["svg_path"])
            link_dict = {a[1]: a[0] for a in all_linkdata if a}
            # all_svg, all_latex = [], []
            for n, jax in enumerate(all_mathjax):
                svgs = re.findall("<svg .*?</svg>", jax[1])
                latex = re.findall('<script .+?">(((?!(</)).)*?)</script>(</span>)*', jax[1])

                if latex and svgs:
                    latex_sub = re.sub(r"\\text{\s*\}|[{\}]", "", latex[0][0])
                    if latex and not latex_sub.strip():
                        # id_idx = bisect_left(topicidx, jax[0])  # based on 索引而展开二分法查找
                        logger.info("----【paper_id:{}】第{}题存在mathjax公式为空:latex:{}\nsvg:{}".format(
                            self.wordid, jax[0], latex, svgs))  # topicno[id_idx - 1]
                    else:
                        ltx2svgcss["{}".format(latex[0][0])] = svgs[0]  # latex去重
                else:
                    # id_idx = bisect_left(topicidx, jax[0])  # based on 索引而展开二分法查找
                    logger.info("----【paper_id:{}】第{}题存在mathjax公式格式有问题:latex:{}\nsvg:{}".format(
                        self.wordid, jax[0], latex, svgs))
                    if latex:
                        return "第{}题的公式latex：{}不规范,请编辑正确！".format(jax[0], latex[0][0])
                    else:
                        return "第{}题的存在不规范的公式,,请重新编辑！".format(jax[0])

            if ltx2svgcss:
                if not os.path.exists(file_path):
                    os.makedirs(file_path)
                svg_mjmath_path = os.path.join(file_path, "svg_mjmath")
                if not os.path.exists(svg_mjmath_path):
                    os.makedirs(svg_mjmath_path)
                else:  # 需要清空
                    shutil.rmtree(svg_mjmath_path)
                    os.makedirs(svg_mjmath_path)
                n = 0
                name_list = random.sample(range(100000, 999999), len(ltx2svgcss))  # 随机数
                for ltx, svg in ltx2svgcss.items():
                    linkkeys = list(set(re.findall(' xlink:href="#(.*?)"', svg)))
                    linkvalues = [link_dict[ld] for ld in linkkeys]
                    svg_p = file_path + "/svg_mjmath/MJMATH-{}.svg".format(str(int(time.time())) + str(name_list[n]))
                    fs = open(svg_p, 'w', encoding='utf8')
                    svg_1, svg_2 = svg.split("<g ", maxsplit=1)
                    fs.write(svg_1)
                    fs.write('<defs id="MathJax_SVG_glyphs">\n' + "\n".join(linkvalues) + "\n</defs>")
                    fs.write("<g " + svg_2)
                    fs.close()
                    svgp_ltx[svg_p] = ltx
                    n += 1
            logger.info(json.dumps({"log_level": "info",
                                    "paper_id": self.wordid,
                                    "mathjax2svg_time": time.time() - time3,
                                    "svgp_ltx": svgp_ltx}, ensure_ascii=False).encode("utf-8"))
            time4 = time.time()
            # 2.2>>svg转png
            if svgp_ltx:
                try:
                    with ThreadPoolExecutor(max_workers=6) as t:
                        all_png_info = [t.submit(svg2png, arg) for arg in svgp_ltx.keys()]
                except Exception as e:
                    logger.info(json.dumps({"log_level": "warn",
                                            "paper_id": self.wordid,
                                            "status": "svg2png失败",
                                            "errmsg": str(e)}, ensure_ascii=False))
                    all_png_info = []
                all_png_info = [i.result() for i in all_png_info]
                for shape, img_path in all_png_info:
                    local_mjmath.append(img_path)
                    imgname_online = "/zyk/uploadfiles/wording/" + str(self.wordid) + "/{}".format(os.path.basename(img_path))
                    put_key_mjmath.append(imgname_online)
                    mj_ltx = svgp_ltx[img_path.replace(".png", ".svg")]  #.replace("\\\\", "\\")
                    w = shape[0] / 4 * 1.2
                    h = shape[1] / 4 * 1.2
                    if re.search(r"^{?[A-Z、\s{_\}\d]+\}?$", mj_ltx):
                        w = shape[0] / 4
                        h = shape[1] / 4
                    mjmath_online = '<img src="http://' + configs.public_bucket_addr + imgname_online \
                                    + '" width="{}" height="{}" data-type="math" data-latex="{}" />'.format(
                        int(w), int(h), "${}$".format(mj_ltx))  # shape[0] / 2
                    self.ltx2url[mj_ltx] = mjmath_online
            logger.info(json.dumps({"log_level": "info",
                                    "paper_id": self.wordid,
                                    "svg2png_time": time.time() - time4,
                                    "ltx2url": self.ltx2url}, ensure_ascii=False))
        return put_key_mjmath, local_mjmath

    def upload_img(self):
        """
        items_list：结构化纯文本
        htmlt:ocr或word解析后的html文本
        svg_data：{"svg_html_data": "", "svg_path": ""} 含svg数据的结构化整体html文本,svg中的索引数据
        wordid：试卷存储id
        callback_url: 回调地址
        入库操作包含：
            1、再解析后确认入库时，将image上传,htmlt中图片；
            2、学管端可以是组合（文本+图片）的解析结果。学管可以选择和修改文本，但选择的文本解析时都会替换原先的img标签内容，
               最后入库时，传回学管端的都是带img标签的结果
            3、传回学管端和共享题库的题目中的$$公式要转换为图片；
               $$左右还有公式字符串的话，在结构化过程中一起并入！！！
            4、调取查重关联功能，暂时不调自动标注；
            5、传入校本题库（发送标注），将结构化后的每道题设置个与大数据资源库的关联标签，如"zyk_id":id+题号

        5种图片：1>>ser_static/.*?/word/media(解析服务中最开始保存在线上服务器本地)
                2>>/zyk/uploadfiles/wording/(解析服务中上传到腾讯云)
                3、4>>ser_static/.*?/(new_image[^"]*?|eq_img_\d.png):批量再解析和单题再解析中，
                   用户在编辑页面新粘贴进来的base64图片，以及批量再解析中域公式转图片，临时存在结构化服务器本地
                5、利用mathjax渲染latex的svg格式转为png，再上传到腾讯云
        上传之前，将腾讯云桶里的new_image全部替换，raw_image判断下再替换
        items_list:list 所有题目
        :return:
               res_zyk = {"data":{"html": xxx, "items": xxx}, "errcode": 0, "errmsgs": ""}
               res_xbk = {"items": xxx, "errcode": 0, "errmsg":"ok"}
        """
        # if not self.items_list:
        #     return {"errcode":1, "errmsgs": "无结果，不能入库", "data":{}}
        #
        # # if any([True if "stem_img" not in i and "stem" not in i else False
        # #         for i in self.items_list]):  # 存在新增的空试题时，只有3个字段type,img_status,check_type
        # #     return {"errcode":1, "errmsgs": "存在空试题，请检查！", "data":{}}
        # contain_id = []
        # for i in self.items_list:
        #     if "stem_img" not in i and "stem" not in i:
        #         return {"errcode": 1, "errmsgs": "存在空试题，请检查！", "data": {}}
        # if contain_id:
        #     return {"errcode": 1, "errmsgs": "存在报错试题【{}题】还没改正过来，请检查！".format("、".join(contain_id)), "data": {}}

            # elif "errmsgs" in i and i["errmsgs"]:
            #     return {"errcode": 1, "errmsgs": "存在报错试题还没改正过来，请检查！", "data": {}}

        res_xbk = {"items": [], "errcode": 0, "errmsg": "ok", "callback_type": 2, "subject_id": self.subject}
        res_zyk = {"errcode": 0, "errmsgs": "", "data": {"html": self.htmlt, "items": self.items_list}}
        # 1>>判断删除腾讯云桶内图片
        # self.bucket_img_del()
        # ---------------------------------------------------------------------
        # 1.2>>将zyk/uploadfiles/wording/ 路径的缺latex的公式图片，再调mathpix接口拿到latex填充
        # 2>>mathjax渲染的svg图片提取->保存->格式转化
        svg_convert_res = self.mathjx2png()
        if type(svg_convert_res) == str:
            res_xbk = {"items": [], "errcode": 1, "errmsg": svg_convert_res, "callback_type": 2, "subject_id": self.subject}
            res_zyk = {"errcode": 1, "errmsgs": svg_convert_res, "data": {}}
            if self.callback_url:
                self.callback_user(res_xbk, self.callback_url)
                if self.source == "xue_guan":
                    self.callback_php(res_xbk)  # 失败时就不发送数据库端了,但学管端时发送
            return res_zyk
        put_key_mjmath, local_mjmath = svg_convert_res
        # --------------------------------------------------------------------
        # 3>> 统计 ocr和结构化试题 中的新图片，以防结构化入库的试题少了而导致图片上传不足，左边页面无法显示
        put_key_list = []  # 桶中key
        localnewpic_list = []  # 本地图片存储位置
        imgs_url_list = []  # 远程服务器上图片存储位置
        put_key_imgsurl = []
        new_imgs = re.findall(r'<img src=".*?/ser_static/.*?/(new_image[^"]*?|eq_img_\d+\.png)"', str(self.htmlt))
        new_imgs2 = re.findall(r'<img src=".*?/ser_static/.*?/(new_image[^"]*?|eq_img_\d+\.png)"', str(self.items_list))
        new_imgs.extend(new_imgs2)
        # print(new_imgs)
        new_imgs = list(set(new_imgs))
        if new_imgs:
            put_key_list.extend(["/zyk/uploadfiles/wording/" + str(self.wordid) + "/{}".format(img_name)
                                 for img_name in new_imgs])
            file_path = configs.IMG_FOLDER + "/" + str(self.wordid)
            localnewpic_list.extend([file_path + "/field_eq/" + img_name if "eq_img_" in img_name
                                     else file_path + "/" + img_name for img_name in new_imgs])

        old_imgs = re.findall(r'<img src="(.*?/ser_static[/\\](.*?/word/media)/(image[^"]*?))"', str(self.htmlt))
        print("old_imgs:", old_imgs)
        if old_imgs:  # 针对最开始入库的情况，后期都直接在wordbin时就上传腾讯云了
            # 以前新添加的图片在左预览页仍以base64保存，若再解析，则会按新的方法保存到本地
            # 只是最开始解析的老图片是保存在服务器本地的，若入库时，则一起拿出来再上传腾讯云
            if configs.external_ip not in old_imgs[0][0]:  # 非本地图片
            # if '82.156.255.225' not in old_imgs[0][0]:
                imgs_url_list.extend([img_name[0] for img_name in old_imgs])
                put_key_imgsurl.extend(["/zyk/uploadfiles/wording/" + str(self.wordid) + "/{}".format(img[2])
                                        for img in old_imgs])
            else:  # 本地图片
                file_path = configs.RawImg_UploadFolder + "/" + old_imgs[0][1]
                put_key_list.extend(["/zyk/uploadfiles/wording/" + str(self.wordid) + "/{}".format(img[2])
                                     for img in old_imgs])
                localnewpic_list.extend([file_path + "/" + img[2] for img in old_imgs])
        # print('*****************************put_key_list*******************************')
        # print(put_key_list)
        # print('*****************************localnewpic_list*******************************')
        # print(localnewpic_list)
        if self.callback_url:
            put_key_list.extend(put_key_mjmath)
            localnewpic_list.extend(local_mjmath)
        # ------------------------------------------------------------------------------------------

        items_res_to_xbk = []
        repeat_time = 0
        # kps_label_time = 0
        if localnewpic_list or imgs_url_list:  # 本地有新图片时
            new_img_online = '<img src="http://' + configs.public_bucket_addr + "/zyk/uploadfiles/wording/" + str(self.wordid)
            new_img_local = '<img src="' + configs.new_img_ip + '/' + str(self.wordid)  # 结构化中产生的图片
            old_img_local = ""  # wordbin最初产生的图片
            if old_imgs:
                # new_img_local = '<img src="' + configs.old_img_ip + '/' + old_imgs[0][0]
                old_img_local = '<img src="' + old_imgs[0][0].split("ser_static")[0]+"ser_static" + '/' + old_imgs[0][1]

            def sub1(s):
                """图片访问地址替换,本地替换为线上"""
                if s:
                    s = re.sub(r'(<img src="[^"]*?[a-z\d])\\(?!\\)([^"]*?")', r"\1/\2", str(s))  # 将路径中的\改为/
                    s = s.replace(new_img_local, new_img_online)
                    if old_img_local:
                        return s.replace(old_img_local, new_img_online)
                return s

            def sub2(s):
                """将试题中的latex转为线上可访问图片地址"""
                if s:
                    all_ltx = re.findall(r'\$.*?\$', s)  # 查找试题结构中的公式
                    all_ltx.extend(re.findall('\\\\\(.*?\\\\\)', s))
                    all_ltx = list(set(all_ltx))
                    for ltx in all_ltx:
                        new_ltx = ltx.replace("$", "").replace("\\(", "").replace("\\)", "")\
                            .replace("&amp;", "&").replace("&lt;", "<")  #.replace(" ", "\\u200a")
                        if new_ltx in self.ltx2url:  # 将latex换为其渲染图片的线上可访问地址
                            s = s.replace(ltx, self.ltx2url[new_ltx])
                        else:
                            logger.info("----【word_id:{}】latex替换为imgurl失败：{}".format(self.wordid, new_ltx))
                    s = re.sub(r' data-latex="<img .*?data-latex=(".*?").*?/>"\s*/>', r" data-latex=\1 />", s)
                return s

            def ltx2url_repl(one_items):
                """
                将每道题结构中的各字段进行匹配替换  ltx2url
                """
                keys_items = ["stem", "key", "parse", "options", "slave"]
                if self.ltx2url:
                    for k in keys_items:
                        if k in one_items:
                            if k == "options":
                                one_items[k] = list(map(sub2, one_items[k]))
                            elif k == "slave" and one_items[k]:
                                for slave_one in one_items[k]:
                                    ltx2url_repl(slave_one)
                            else:
                                one_items[k] = sub2(one_items[k])
                        # else:
                        #     if "topic_num" in one_items:
                        #         logger.info("----【word_id:{}】第{}道题{}字段有问题".format(self.wordid, one_items["topic_num"], k))
                        #     else:
                        #         logger.info("----【word_id:{}】{}字段有问题".format(self.wordid, k))
            # -------------------------------------------------------------

            time6 = time.time()
            # 4>> 结构化题目中图片地址替换,需要区分下学管端还是云题库！！！！！一定会保存一份在资源库
            items_res_to_zyk = self.items_list.copy()
            items_res_to_zyk = eval(sub1(items_res_to_zyk))
            # for one_items in items_res_to_zyk:
            #     for k in ["stem", "key", "parse", "options"]:  # "analysis",
            #         if k in one_items:
            #             if k == "options":
            #                 one_items[k] = list(map(sub1, one_items[k]))
            #             else:
            #                 one_items[k] = sub1(one_items[k])

            # -----------难度和知识点自动标注------------------------
            diffs_xbk, items_res_to_zyk = self.get_diff(items_res_to_zyk.copy())   # 难度

            for nn, one_items in enumerate(deepcopy(items_res_to_zyk)):
                new_one_item = {}
                if self.subject == 3:  # "高中数学"
                    new_one_item["difficulty"] = diffs_xbk[nn]
                # if one_items["checkType"]["name"] == "填空题":
                #     new_one_item["blank_num"] = one_items["blank_num"]
                # keys_items = ["stem", "key", "parse", "options"]
                # if one_items['img_status'] == 1 and ("stem_img" in one_items and one_items["stem_img"]):
                #     logger.info("----【paper_id:{}】mathjax2svg所取的字段是带img的".format(self.wordid))
                #     keys_items = ["stem_img", "key_img", "parse_img", "options_img"]
                if self.callback_url:
                    # 查重
                    if self.source != "xue_guan":
                        repeat_r, repeat_time = self.repeat_check(nn, one_items, repeat_time)
                        if type(repeat_r) == str:
                            res_xbk = {"items": [], "errcode": 1, "errmsg": repeat_r, "callback_type": 2, "subject_id": self.subject}
                            res_zyk = {"errcode": 1, "errmsgs": repeat_r, "data": {}}
                            self.callback_user(res_xbk, self.callback_url)
                            return res_zyk
                        new_one_item["repeat_res"] = repeat_r
                    new_one_item["topic_type_id"] = one_items["checkType"]["id"]
                    if "options_rank" in one_items and one_items["options_rank"]:
                        new_one_item["options_rank"] = one_items["options_rank"]
                    ltx2url_repl(one_items)
                    one_items = self.slave2regroup(one_items)
                    new_one_item.update(one_items)
                    # for k in keys_items:
                    #     if k in one_items:
                    #         if self.ltx2url:
                    #             if k == "options":
                    #                 one_items[k] = list(map(sub2, one_items[k]))
                    #             else:
                    #                 one_items[k] = sub2(one_items[k])
                    #         new_one_item[k] = one_items[k]
                        # else:  # 有的题本来就没有options字段
                        #     logger.info("----【paper_id:{}】第{}道题{}字段有问题".format(self.wordid, one_items["topic_num"], k))
                items_res_to_xbk.append(new_one_item)

            # 5>> ocr-htmlt中图片地址替换成云上地址
            self.htmlt = re.sub(r'(<img src="[^"]*?[a-z\d])\\(?!\\)([^"]*?")', r"\1/\2", self.htmlt)
            self.htmlt = self.htmlt.replace(new_img_local, new_img_online)
            if old_img_local:
                self.htmlt = self.htmlt.replace(old_img_local, new_img_online)
            logger.info(json.dumps({"log_level": "info",
                                    "paper_id": self.wordid,
                                    "imgurl_repl_time": time.time() - time6,
                                    "repeat_time": repeat_time}, ensure_ascii=False))
            # -----------------------------------------------------------------------
            # 6 >> new_image上传腾讯云
            try:
                logger.info('----【paper_id:{}】再解析开始上传图片到cloud，并替换成线上地址----'.format(self.wordid))
                stime_u = time.time()
                # TODO 一个进程解析，一个进程上传
                executor1 = ThreadPoolExecutor(5)
                executor1.map(upload_img_to_qcloud, zip(put_key_list, localnewpic_list))
                if imgs_url_list:
                    executor1.map(filestream_upload, zip(put_key_imgsurl, imgs_url_list))
                executor1.shutdown(wait=True)  # 进程池内部的进程都执行完毕，才会关闭，然后执行后续代码
                img_upload_time = time.time() - stime_u
                logger.info(json.dumps({"log_level": "info",
                                        "paper_id": self.wordid,
                                        "img_upload_time": img_upload_time}, ensure_ascii=False))
                res_zyk = {"data": {"html": self.htmlt, "items": items_res_to_zyk}, "errcode": 0, "errmsgs": ""}
                res_xbk = {"items": items_res_to_xbk, "errcode": 0, "errmsg": "ok", "callback_type": 2, "subject_id": self.subject}
            except Exception as e:
                res_xbk = {"items": [], "errcode": 1, "errmsg": "公式或图片上传腾讯云失败", "callback_type":2, "subject_id": self.subject}
                res_zyk = {"data":{"html": self.htmlt, "items": self.items_list}, "errcode": 1,
                           "errmsgs": "公式或图片上传腾讯云失败"}
                logger.info(json.dumps({"log_level": "warn",
                                        "paper_id": self.wordid,
                                        "status": "公式或图片上传腾讯云失败",
                                        "errmsg": str(e)}, ensure_ascii=False))
        else:  # 本地没有新图片时
            # -----------难度、知识点自动标注------------------------
            diffs_xbk, self.items_list = self.get_diff(self.items_list)  # 难度
            if self.callback_url:
                for nn, one_items in enumerate(self.items_list):
                    new_one_item = {}
                    if self.subject == 3:  # "高中数学"
                        new_one_item["difficulty"] = diffs_xbk[nn]
                    # 查重
                    if self.source != "xue_guan":
                        repeat_r, repeat_time = self.repeat_check(nn, one_items, repeat_time)
                        if type(repeat_r) == str:
                            res_xbk = {"items": [], "errcode": 1, "errmsg": repeat_r, "callback_type": 2, "subject_id": self.subject}
                            res_zyk = {"errcode": 1, "errmsgs": repeat_r, "data": {}}
                            self.callback_user(res_xbk, self.callback_url)
                            return res_zyk
                        new_one_item["repeat_res"] = repeat_r
                    new_one_item["topic_type_id"] = one_items["checkType"]["id"]
                    if "options_rank" in one_items and one_items["options_rank"]:
                        new_one_item["options_rank"] = one_items["options_rank"]
                    one_items = self.slave2regroup(one_items)
                    new_one_item.update(one_items)
                    # keys_items = ["stem", "key", "parse", "options"]
                    # for k in keys_items:
                    #     if k in one_items:
                    #         new_one_item[k] = one_items[k]
                    items_res_to_xbk.append(new_one_item)

                res_xbk = {"items": items_res_to_xbk, "errcode": 0, "errmsg": "ok", "callback_type": 2, "subject_id": self.subject}
                logger.info(json.dumps({"log_level": "info",
                                        "paper_id": self.wordid,
                                        "repeat_time": repeat_time}, ensure_ascii=False))
        # 先传一份到校本题库，再返回结果
        if self.callback_url:
            #  知识点自动标注--批量
            if self.subject == 3 and self.source == "qtk": # "高中数学"
                try:
                    res_xbk = self.get_kps_auto(res_xbk)
                except Exception as e:
                    logger.info("----【paper_id:{}】高中数学标注异常：{}".format(self.wordid, e))
            # 回调前，将结果保存本地一份
            self.save_post_file(res_xbk)
            have_err = self.callback_user(res_xbk, self.callback_url)
            if self.source == "xue_guan" or not have_err:   # 失败时就不发送数据库端了,但学管端时发
                self.callback_php(res_xbk)

        return res_zyk

    def slave2regroup(self, one_items):
        """
        将拆分的小题根据是否为旧题型进行重组，如果保存时选择的旧题型就要组合成三段式
        对判断题的答案进行转化：正确-->A;错误-->B
        :return:
        """
        # 此阶段将每个题可能的报错信息去掉
        if "errmsgs" in one_items and one_items["errmsgs"]:
            one_items["errmsgs"] = ""
        if "btt_id" not in one_items["checkType"] or one_items["checkType"]["btt_id"] != 13:
            if "slave" in one_items and one_items["slave"]:  # 带小题的
                for idn, s in enumerate(one_items["slave"]):
                    if not one_items["stem"] and not idn and s["stem"].strip():
                        one_items["stem"] += "(1)" + s["stem"]
                    elif s["stem"].strip():
                        one_items["stem"] += "<br/>({})".format(idn + 1) + s["stem"]
                    if not one_items["key"] and not idn and s["key"].strip():
                        one_items["key"] += "(1)" + s["key"]
                    elif s["key"].strip():
                        one_items["key"] += "<br/>({})".format(idn + 1) + s["key"]
                    if not one_items["parse"] and not idn and s["parse"].strip():
                        one_items["parse"] += "(1)" + s["parse"]
                    elif s["parse"].strip():
                        one_items["parse"] += "<br/>({})".format(idn + 1) + s["parse"]
                    if "options" in s and s["options"]:
                        one_items["stem"] += "<br/>" + "<br/>".join(["{}、{}".format(chr(ord('@') + idm + 1),
                                                         option) for idm, option in enumerate(s["options"])])
                one_items["slave"] = []
            if "btt_id" in one_items["checkType"] and one_items["checkType"]["btt_id"] not in [5, 6, 7]:
                one_items["stem"] = re.sub(r'<span style="color:RGB\(50%,40%,30%\); blank space">(__{2,})</span>',
                                           r"\1", one_items["stem"])
        else:
        # if "btt_id" in one_items["checkType"] and one_items["checkType"]["btt_id"] == 13:
            # 将小问答案没拆出来的部分放入公共解析字段中
            if "slave" in one_items and one_items["slave"] and one_items["key"] and \
                    all([True if not s["key"].strip() else False for s in one_items["slave"]]):  # 带小题的且小题答案都为空
                if one_items["parse"].strip():
                    one_items["parse"] = "【答案】\n{}\n【解析】\n{}".format(one_items["key"], one_items["parse"])
                else:
                    one_items["parse"] = "【答案】\n{}".format(one_items["key"])
                one_items["key"] = ""

        if "btt_id" in one_items["checkType"] and one_items["checkType"]["btt_id"] == 12:  # 判断题
            one_items["answer_type"] = 4
            if re.match("(?<!不)对|(?<!不)正确|[T√]$", one_items["key"]):
                one_items["key"] = "正确"
            elif re.match("错误?的?|不对的?|不正确的?|[F×]$", one_items["key"]):
                one_items["key"] = "错误"
        return one_items

    def save(self):
        """
        入口函数
        :return:
        """
        res_xbk = {"items": [], "errcode": 1, "errmsg": "保存失败", "callback_type": 2, "subject_id": self.subject}
        try:
            res_zyk = self.upload_img()
            return res_zyk
        except Exception as e:
            print("------【paper_id:{}】最后的保存失败:{}-------".format(self.wordid, str(e)))
            logger.info(json.dumps({"log_level": "warn",
                                    "paper_id": self.wordid,
                                    "status": "入库失败",
                                    "errmsg": str(e),
                                    "task_name": "保存入库"}, ensure_ascii=False))
            if self.callback_url:
                self.callback_code = 1
                self.callback_err = "保存失败"
                self.callback_user(res_xbk, self.callback_url, err="1")
                if self.source == "xue_guan":
                    self.callback_php(res_xbk)   # 失败时就不发送数据库端了,但学管端时发

        return {"errcode": 1, "errmsgs": "入库失败！", "data": {}}


    def save_post_file(self, parse_res):
        """保存回调的数据解析结果"""
        now_time = datetime.datetime.now()
        time_str = datetime.datetime.strftime(now_time, '%Y_%m_%d_%H_%M_%S')
        # aft_modify = (str("word_name") + '__' + str(random.random())).encode("utf-8")
        # hh = hashlib.md5(aft_modify).hexdigest()
        aft_name = self.wordid + '__' + time_str + '.json'
        res_folder = configs.RES_FOLDER  # 保存的文件夹
        new_fpath = os.path.join(res_folder, aft_name)
        re_f = open(new_fpath, 'w', encoding='utf-8')
        json.dump(parse_res, re_f,ensure_ascii=False)

    def get_kps_auto(self, all_items):
        """
        调取自动标注的端口获取考点
        :return:
        """
        def phy_kps(input_data):
            label_auto = {}
            if input_data:
                r = requests.post(configs.kps_phy_ip, json=input_data)  # json={"input_data": item}
                if r.status_code == 200:
                    res = r.json()['result']  # eval(r.text)
                    if res:
                        label_auto.update(res)
            return label_auto

        def Hmath_kps(input_data):
            label_auto = []
            try:
                r = requests.post(configs.kps_Hmath_ip, json=input_data)  # json={"input_data": item}
                if r.status_code == 200:
                    res = r.json()  # eval(r.text)
                    if res and 'data' in res:
                        label_auto = res['data']
            except Exception as e:
                logger.info("----【paper_id:{}】标注服务异常：{}".format(self.wordid, e))
                return "保存入库高中数学标注服务异常"
            return label_auto

        t1= time.time()
        # 高中物理
        # temp_items = {"server_state": 11,
        #               "fine_state": 0,
        #               "add_parse_state": 1}
        # one_info = {"topic_id": one_items["topic_num"],
        #             "content": one_items["stem"],
        #             "option": one_items["options"] if "options" in one_items else [],
        #             "parse": one_items["parse"],
        #             "kpl_codes": [], "ori_sences": [], "ori_kpl_codes": [],
        #             "topic_type_id": one_items["checkType"]["id"]}
        # temp_items["info"] = one_info
        # 高中数学
        # stems = one_items["stem"]
        # if "slave" in one_items and one_items["slave"]:
        #     stem_l = [s["slave_no"] + s["stem"] + "<br/>"+ "<br/>".join(s["options"])
        #               if "options" in s and s["options"] else s["slave_no"] + s["stem"] for s in one_items["slave"]]
        #     stems += "<br/>".join(stem_l)
        items = all_items["items"]
        items_info = {"subject_id": self.subject,
                     "topics": [{"topic_id": "123",  # one_items["id"]
                                 "topic_type_id": one_items["checkType"]["id"],
                                 "content": one_items["stem"],
                                 "parse": one_items["parse"] if "parse" in one_items else "",
                                 "option": one_items["options"] if "options" in one_items else [],
                                 "resource_type": 0,
                                 "slave": one_items["slave"] if "slave" in one_items else []} for one_items in items]
                     }

        auto_kps = Hmath_kps(items_info)
        if  not auto_kps or type(auto_kps) == str:
            pass
        else:
            for nn, one_items in enumerate(all_items["items"]):
                one_items.update({"auto_mark_result": auto_kps[nn]})
            # all_items["items"] = [lambda x:one_items.update({"auto_mark_result": auto_kps[nn]})
            #                       for nn, one_items in enumerate(all_items["items"])]
        # print("自动标注考点：", auto_kps)
        logger.info(json.dumps({"log_level": "info",
                                "paper_id": self.wordid,
                                "automark_time": time.time() - t1}, ensure_ascii=False))
        return all_items

    def img2latex(self):
        # 3>> 统计结构化试题data-latex为空的图片，再ocr-latex处理并替换
        time5 = time.time()
        items_str = str(self.items_list)
        all_imgs_no_latex = re.findall(r'(<img src="(.*?)".*? data-latex="\$?\s*\$?")', items_str)
        if all_imgs_no_latex:
            imgurl_no_latex = [k[1] for k in all_imgs_no_latex]
            imgurl_no_latex = list(set(imgurl_no_latex))
            mathpixs = []
            try:
                if len(imgurl_no_latex) <= 20:
                    mathpixs.extend([get_ocrlatex_by_url(i) for i in imgurl_no_latex])
                else:
                    if len(imgurl_no_latex) <= 50:
                        executor = ThreadPoolExecutor(max_workers=2)  # 开2个线程会稍微快点
                    else:
                        executor = ThreadPoolExecutor(max_workers=4)
                    for data in executor.map(get_ocrlatex_by_url, imgurl_no_latex):
                        mathpixs.append(data)
                logger.info("----【paper_id:{}】latex-ocr：{}".format(self.wordid, mathpixs))

                def sub3(ss):
                    new_ss = ss.group(1) + ' data-type="math-ocr" data-latex="$' + mathpixs[mi] + '$"' + ss.group(2)
                    return new_ss.replace(' data-type="math"', "")
                    # return ss.group(1) + 'data-type="math-ocr" data-latex="$' + mathpixs[mi] + '$"'

                for mi, m in enumerate(imgurl_no_latex):
                    # items_str = re.sub(r'(<img src="{}".*?) data-latex="\$?\s*\$?"'.format(m), sub3, items_str)
                    if mathpixs[mi]:
                        items_str = re.sub(r'(<img src="{}".*?) data-latex="\$?\s*\$?"(.*?(?<=")\s*/?>)'.format(m),
                                           sub3, items_str)
                self.items_list = eval(items_str)
                logger.info("----【paper_id:{}】结构化试题中空latex掉mathpix转化时间：{}".format(self.wordid, time.time() - time5))
            except:
                logger.info("----【paper_id:{}】latex-ocr转化过程失败".format(self.wordid))
        # -------------------------------------------------------------------

    def get_diff(self, items_res_to_zyk):
        # -----------难度自动标注------------------------
        # t11 = time.time()
        diffs_xbk = [3] * len(items_res_to_zyk)
        # if self.subject == "高中数学":  # 难度自动标注暂时不用了
        #     from multiprocessing.dummy import Pool as ThreadPool
        #     pool = ThreadPool(2)  # 比# pool = multiprocessing.Pool(3)速度快
        #     diff_info = list(pool.map(get_item_diff, items_res_to_zyk))
        #     items_res_to_zyk = [f[0] for f in diff_info]
        #     diffs_xbk = [f[1] for f in diff_info]
        #     logger.info("----【paper_id:{}】结构化试题中难度标注时间：{}".format(self.wordid, time.time() - t11))
        return diffs_xbk, items_res_to_zyk

    def repeat_check(self, id, one_items, repeat_time):
        t22 = time.time()
        stems = one_items["stem"]
        # if "slave" in one_items and one_items["slave"]:
        #     stem_l = [s["slave_no"] + s["stem"] + "<br/>"+ "<br/>".join(s["options"])
        #               if "options" in s and s["options"] else s["slave_no"] + s["stem"] for s in one_items["slave"]]
        #     stems += "<br/>".join(stem_l)
        chachong_item_dict = {"topic_id": id + 1,
                              "subject_id": self.subject,
                              "topic_type_id": one_items["checkType"]["id"],
                              "content": stems}
        if "slave" in one_items:
            chachong_item_dict["slave"] = one_items["slave"]
        if "options" in one_items:
            chachong_item_dict["options"] = one_items["options"]

        # print(chachong_item_dict)
        try:
            repeat_r = requests.post(url=configs.repeat_ip, json=[chachong_item_dict]).json()

            print("查重结果：", repeat_r)  # [str(id + 1)]
            if repeat_r:
                repeat_r = repeat_r[str(id + 1)]
            else:
                repeat_r = []
        except Exception as e:
            logger.info("----【paper_id:{}】查重服务异常：{}".format(self.wordid, e))
            repeat_r = "保存入库查重服务异常"
        repeat_time += time.time() - t22
        return repeat_r, repeat_time

    def callback_user(self, res_xbk, callback_url, err=""):
        """全学科题库、第三方上传试卷回调"""
        have_err = 0
        if not err:
            if res_xbk["errcode"]:
                have_err = 1
                logger.info(json.dumps({"log_level": "info",
                             "paper_id": self.wordid,
                             "status": "入库失败",
                             "errmsg": res_xbk["errmsg"],
                             "task_name": "保存入库"}, ensure_ascii=False))
            else:
                logger.info(json.dumps({"log_level": "info",
                             "paper_id": self.wordid,
                             "status": "入库成功",
                             "task_name": "保存入库"}, ensure_ascii=False))
        try:
            r = requests.post(callback_url,
                              # json=res, # 可以,但是会进行转义
                              headers={"Content-Type":"application/json"},
                              data=json.dumps(res_xbk, ensure_ascii=False).encode("utf-8"),  # 文件开头有编码显示
                              )
            print("------【paper_id:{}】,post 回调地址状态：{}===>回调结果: {} -------\n".format(self.wordid, r.status_code, r.text))
            if r.status_code != 200:
                have_err = 1
            if r.text != "解析完成！":
                have_err = 1
            logger.info(json.dumps(
                        {"log_level": "info",
                         "paper_id": self.wordid,
                         "callback_res": {"status": "回调成功" if r.status_code == 200 else "回调失败",
                                          "status_code": r.status_code,
                                          "text": str(r.text),
                                          "callback_url": callback_url},
                         "task_name": "入库回调"}, ensure_ascii=False))
        # except TimeoutError:
        #     # print("回调超时")
        #     callback_err += "回调超时"
        #     logger.info("------【paper_id:{}】回调超时-------".format(self.wordid))
        except Exception as e:
            self.callback_err += "回调出错"
            self.callback_code = 1
            have_err = 1
            print("------【paper_id:{}】回调出错:{}-------".format(self.wordid, e))
            logger.info(json.dumps(
                        {"log_level": "warn",
                         "paper_id": self.wordid,
                         "callback_res": {"status": "回调失败",
                                          "callback_url": callback_url},
                         "errmsg": str(e),
                         "task_name": "入库回调"}, ensure_ascii=False))
        else:
            if r.status_code != 200:
                have_err = 1
                self.callback_code = 1
                self.callback_err = "回调出错:{}".format(r.status_code)
                logger.info(json.dumps(
                            {"log_level": "warn",
                             "paper_id": self.wordid,
                             "callback_res": {"status": "回调失败",
                                              "status_code": r.status_code,
                                              "text": r.text,
                                              "callback_url": callback_url},
                             "task_name": "入库回调"}, ensure_ascii=False))
        return have_err

    def callback_php(self, res_xbk):
        """
        将解析校对完的试题返回数据库端
        :param res_xbk: 返回给其它端的数据
        :return:
        """
        if res_xbk["errmsg"] not in ["ok", "保存失败"]:  #公式上传腾讯云失败等
            self.callback_err += res_xbk["errmsg"]
            if self.callback_err:
                self.callback_code = 1
        type_check = {"errcode": self.callback_code,
                      "errmsg": self.callback_err,
                      "parseId": self.wordid,
                      "callback_type": 2,
                      "data": [k["checkType"]["id"] for k in self.items_list],
                      }
        try:
            r2 = requests.post(configs.callback_url_taskcheck,
                               data=json.dumps(type_check, ensure_ascii=False).encode("utf-8"))
            print("------【paper_id:{}】taskcheck post数据：{} 回调地址状态：{}===>回调结果: {}-------".format(
                self.wordid, type_check, r2.status_code, r2.text))
            logger.info(json.dumps({"log_level": "info",
                         "paper_id": self.wordid,
                         "callback_data": type_check,
                         "callback_res": {"status": "回调成功" if r2.status_code == 200 else "回调失败",
                                          "status_code": r2.status_code,
                                          "text": r2.text,
                                          "callback_url": configs.callback_url_taskcheck},
                         "task_name": "入库回调"}, ensure_ascii=False))
        except Exception as e:
            print("------【paper_id:{}】taskcheck回调出错:{}-------".format(self.wordid, e))
            logger.info(json.dumps({"log_level": "warn",
                     "paper_id": self.wordid,
                     "callback_data": type_check,
                     "callback_res": {"status": "回调失败",
                                      "callback_url": configs.callback_url_taskcheck},
                     "errmsg": str(e),
                     "task_name": "入库回调"}, ensure_ascii=False))
        else:
            if r2.status_code != 200:
                print("------【paper_id:{}】taskcheck回调出错:{}".format(self.wordid, r2.status_code))
                logger.info(json.dumps({"log_level": "warn",
                             "paper_id": self.wordid,
                             "callback_data": type_check,
                             "callback_res": {"status": "回调失败",
                                              "status_code": r2.status_code,
                                              "text": r2.text,
                                              "callback_url": configs.callback_url_taskcheck},
                             "task_name": "入库回调"}, ensure_ascii=False))

if __name__ == '__main__':
    from pprint import pprint
    import pickle
    # items_list = [{'id': '60bdcd734a5335001b0a73cf', 'type': '填空题',
    #                'stem': '在数列\\({\\lbrace a_{n}\\rbrace }\\)中，若\\({a_{1}=1,a_{n}-a_{n-1}=n(n\\geq 2),}\\)则该数列的通项\\({a_{n}=}\\)',
    #                'options': [], 'key': '\\( \\frac{1}{2} \\) \n ',
    #                'subject': '数学', 'errmsgs': '', 'topic_num': 0, 'parse_img': '略', 'analysis': '', 'slave_img': '',
    #                'parse': '略 \n \n ', 'category': ['月考'], 'grade': '高一',
    #                'stem_img': "<img src='http://zxhx-1302712961.cos.ap-shanghai.myqcloud.com/imgpaper/lqy_upload/img_5fc0d256407550d0b7d9a43c_56.png' width='305' height='18' />", 'period': '高中',
    #                'province': '湖北', 'susp_pic': None, 'option_str': '', 'blank_num': None, 'year': 2020, 'difficulty': '中',
    #                'specials': [], 'upload_time': '2021-07-16T13:51:49.561000Z',
    #                'key_img': "<img src='http://zxhx-1302712961.cos.ap-shanghai.myqcloud.com/imgpaper/lqy_upload/ans_img_5fc0d256407550d0b7d9a43c_0.png' width='106' height='17' />", 'options_img': [],
    #                'options_rank': None, 'text_status': None, 'img_status': 1,
    #                'source': {'type': 's',
    #                           'related_exampaper': [{'paper_id': '5fc0d256407550d0b7d9a43c',
    #                                                  'file_name': '十堰市一中 2019 级高一下4月月考  数学试题包含答案 ',
    #                                                 'item_id': None}]}}]
    # ocr_html = r'数学<br/>命题人:王旭辉<br/>一、选择题(本大题共12小题，每小题5分,请将正确答案填涂在答题卡相应的位置。)<br/>1.cos80°sin40°+sin50°cos10°的值为()<br/>A.${\quad \frac{1}{2}}$B.${\quad \frac{\sqrt {2}}{2}}${c.\quad \frac{\sqrt {3}}{2}}${b.\quad -\frac{\sqrt {3}}{2}}$<br/>2.已知在等比数列${\lbrace a_{n}\rbrace }$中，${a_{1}=1,\quad a_{5}=9,}${a_{3}=(\quad }$<br/>B.±5.±3D.3<br/>3.已知a>b>0,则下列不等式成立的是()<br/>A.${\quad a>b>\frac{a+b}{2}>\sqrt {ab}}$B.${\quad a>\frac{a+b}{2}>\sqrt {ab}>b}$<br/>${c.\quad a>\frac{a+b}{2}>b>\sqrt {ab}}$D.${\quad a>\sqrt {ab}>\frac{a+b}{2}>b}$<br/>4.给出下列命题:<br/>①棱柱的侧棱都相等,侧面都是全等的平行四边形;<br/>②用一个平面去截棱锥，棱锥底面与截面之间的部分是棱台;<br/>③半圆绕着它的直径所在的直线旋转一周所形成的曲面叫做球面;<br/>④棱台的侧棱延长后交于一点，侧面是等腰梯形.<br/>其中正确命题的序号是()<br/>A.①②④B.①②③C.②③).③<br/>5.已知向量a${i=(1,2),\vec {b}=(2,-2),\quad \vec {c}=(\lambda ,-1)}$，若${\vec {c}//(2\vec {a}+\vec {b})}$则λ=()<br/>A.-2B.-1${c.\quad -\frac{1}{2}}$D.${\quad \frac{1}{2}}$<br/>6.已知△ABC中,a=1,${b=\sqrt {3},}$A=30°,则B等于()<br/>A.30°B.30°或150°C.60°D.60°或120°<br/>7.在△ABC中,a、b、c分别为角A、B、C的对边,若b=2,c=1,C=30°,则a=()()<br/>A.${\quad \sqrt {3}}$B.3C.${\quad \sqrt {5}}$D.1<br/>8.若(a+b+c)(b+c-a)=3bc,且sinA=2sinBcosC,那么△ABC是()<br/>A.直角三角形B.等边三角形<br/>C.等腰三角形D.等腰直角三角形<br/>9.在等差数列${\lbrace a_{n}\rbrace }$中，${S_{15}>0,\quad S_{16}<0,}$则使${a_{n}>0}$成立的n的最大值为()<br/>A.6B.7C.8D.S<br/>10.已知等比数列${\lbrace a_{n}\rbrace }$的前n项和为${S_{n},}${S_{5}=2,\quad S_{10}=6,}${a_{16}+a_{17}+a_{18}+a_{19}+a_{20}=}$<br/>()<br/>A.54B.48C.32D.16<br/>11.设点D为△ABC中BC边上的中点，O为AD边上靠近点A的三等分点,则()<br/>A.${\quad \overrightarrow {BO}=-\frac{1}{6}\overrightarrow {AB}+\frac{1}{2}\overrightarrow {AC}}$B.${\quad \overrightarrow {BO}=\frac{1}{6}\overrightarrow {AB}-\frac{1}{2}\overrightarrow {AC}}$<br/>${\therefore \overrightarrow {BO}=\frac{5}{6}\overrightarrow {AB}-\frac{1}{6}\overrightarrow {AC}}$D.${\quad \overrightarrow {BO}=-\frac{5}{6}\overrightarrow {AB}+\frac{1}{6}\overrightarrow {AC}}$<br/>12.△ABC中,角A、B、C的对边分别为a、b、c,且2a+b=2ccosB,若△ABC的面<br/>积为${S=\sqrt {3}c,}$则ab的最小值为()<br/>A.12B.24C.28D.48<br/>二、填空题(本大题共4小题，每小题5分.请将正确答案填写在答题卡相应位置。)<br/>13.在数列${\lbrace a_{n}\rbrace }$中，若${a_{1}=1,a_{n}-a_{n-1}=n(n\geq 2),}$则该数列的通项${a_{n}=}$<br/>14.已知圆锥的侧面展开图是一个半径为6cm,圆心角为${\frac{2\pi}{3}}$的扇形,则此圆锥的体积为<br/>15.已知平面向量${\vec {a}}${\vec {b}}$的夹角为${\frac{\pi}{3},\quad \vec {a}=(\sqrt {3},-1),\quad |\vec {b}|=1,}$则|${2\vec {a}-\vec {b}|=}$<br/>16.已知α、β为锐角,sinα=2,tan(β-α)=-,则tanβ=______<br/>三.解答题(本大题共6小题，共70分.请将正确答案写在答题卡相应位置。解答应写出<br/>文字说明、证明过程或演算步骤.)<br/>17.(10分)(1)解不等式(x-1)(x-a)≥0<br/>(2)已知${f(x)=\frac{x^{2}+6x+9}{x+1},}$其中x>-1,求f(x)的最小值.<br/>18.(12分)已知函数j${{(x)=2\sin x\cos (x+\frac{\pi}{3})+\frac{\sqrt {3}}{2}}}$<br/>(1)求函数f(x)的最小正周期;<br/>(2)若f(x)+m≤0对${x\∈\lbrack 0,\frac{\pi}{2}\rbrack }$亘成立,求实数m的取值范围.<br/>19.(12分)已知等比数列${\lbrace a_{n}\rbrace }$的前n项和为${S_{n},}$且满足${S_{3}=7,\quad S_{6}=63,}$<br/>(1)求数列${\lbrace a_{n}\rbrace }$的通项公式;<br/>(2)若${b_{n}=a_{n}+\log _{2}a_{n},}$求数列${\lbrace b_{n}\rbrace }$的前n项和${T_{n}}$<br/>0.(12分)已知数列${\lbrace a_{n}\rbrace }$满足${a_{1}=\frac{3}{2},}${l_{n}=\frac{a_{n-1}}{2}+\frac{1}{2^{n-1}}(n\geq 2,n\∈N^{*})}$<br/>(1)求证:数列${\lbrace 2^{n}a_{n}\rbrace }$是等差数列,并求出数列${\lbrace a_{n}\rbrace }$的通项公式;<br/>(2)求数列${\lbrace a_{n}\rbrace }$的前n项和${S_{n}.}$<br/>21.(12分)如图,在△ABC中，${C=\frac{\pi}{4},\overrightarrow {CA}\cdot \overrightarrow {CB}=48,}$点D在BC边上，且<br/>${AD=5\sqrt {2},\cos \angle ADB=\frac{3}{5}}$<br/>(I)求AC,CD的长;(II)求cos∠BAD的值.<br/>22.(12分)数列{a,}中,a,=1,当n≥2时,其前n项和S,满足S,2=a,(S,--)${(u_{n})^{\prime }//t_{1},\quad u_{1}-}${4b_{n}//A_{n}-u_{n}\cdot (\beta _{n}-\bar {2})}$<br/>(1)求${S_{n}}$的表达式;<br/>(2)求数列${\lbrace a_{n}\rbrace }$的通项公式;<br/>(3)设${b_{n}=\frac{S_{n}}{2n+1}.}$求数列${\lbrace b_{n}\rbrace }$的前n项和${T_{n}.}$<br/>数学答案<br/>一、选择题<br/>二、填空题<br/>${13.\frac{n^{2}+n}{2}\quad 14.\frac{16\sqrt {2}}{3}\pi\quad 15.\sqrt {13}\quad 16.\frac{73}{9}}$<br/>三、解答题<br/>17.(1)当a>1时,原不等式解集是{x|x≥a,或x≤1};<br/>当a=1时,原不等式解集是R:<br/>当a<1时,原不等式解集是(x|x|1或X]a}_5分<br/>(2)∵x>-1,则x+1>0,<br/>由基本不等式得${f(x)=\frac{x^{2}+6x+9}{x+1}=}$+1x+1${(x+1)+\frac{4}{x+i}+4}$<br/>${=2\sqrt {(x+1)\cdot \frac{4}{x+1}}+4=8}$(当且仅当${x+1=\frac{4}{x+1}}$时,即当x=1时取得等号)<br/>因此，函数${f(x)=\frac{x^{2}+6x+9}{x+1}(x>-1}$)的最小值为810分<br/>18.解:(1)因为${f(x)=2\sin x\cos (x+}$<br/>${=2\sin x(\cos x\cos \frac{\pi}{3}-\sin x\sin x\sin }$<br/>${=2\sin x(\frac{1}{2}\cos x-\frac{\sqrt {3}}{2}\sin x}$<br/>${\div \sin x\cos x-\sqrt {3}\sin ^{2}x+\frac{\sqrt {3}}{2}}$<br/>${=\frac{1}{2}\sin 2x+\frac{\sqrt {3}}{2}\cos 2x}$<br/>${=\sin (2x+\frac{\pi}{3})}$<br/>所以f(x)的最小正周期为${f=\frac{2\pi}{2}=\pi}$<br/>(2)"f(x)+m≤0对${x\∈\lbrack 0,\frac{\pi}{2}\rbrack }$恒成立"等价于"${f(x)_{\max }+m\leq 0^{n}}$<br/>因为${x\∈\lbrack 0,\frac{\pi}{2}\rbrack }$<br/>所以${2x+\frac{\pi}{3}\∈\lbrack \frac{\pi}{3},\frac{4\pi}{3}\rbrack }$<br/>${2x+\frac{\pi}{3}=\frac{\pi}{2},}${x=\frac{\pi}{12}}$<br/>f(x)的最大值为${f(\frac{\pi}{12})=1.}$<br/>所以实数m的取值范围为${(-9O,-1\rbrack }$12分<br/>19.(1)由题意知S${\because _{6}\neq 2s_{3},q\neq 1\cdots }$<br/>${\therefore S_{3}=\frac{a_{1}(7-q^{3})}{1-q}=7}$<br/>........................3分<br/>${s_{6}=\frac{a_{1}(1-q^{6})}{1-q}}$<br/>解得${\left\lbrace \begin{array}{l}{a_{1}=7}\\{q=2}\end{array}\right.\cdots \cdots }$5分${\therefore a_{n}=2^{n-7}\cdots \cdots }$.6分<br/>2)由(1)知${b_{n}=2^{n-7}+n-1\cdots \cdots \cdots }$..7分<br/>∴T。=(1+2+-..+${y^{-x-3}_{n}}$+[1+2+--+(n-1)].................9分<br/>${=2^{n}+\frac{n^{2}-n}{2}-1\cdots }$.........12分<br/>20.(1)因为${a_{n}=\frac{a_{n-1}}{2}+\frac{1}{2^{n-1}}(n\geq 2,n\∈N^{*})}$，所以${2^{n}a_{n}=2^{n-1}a_{a}+2}$，即<br/>${2^{n}a_{n}-2^{n-1}a_{n-1}=2,}$<br/>所以数列${\lbrace 2^{n}a_{n}\rbrace }$是等差数列,且公差d=2,其首项${2a_{1}=3}$<br/>所以${2^{7}a_{n}=3+(n-1)\times 2=2n+7}$，解得${a_{n}=\frac{2n+i}{2^{n}}}$<br/>${2)\quad S_{n}=\frac{3}{2}+\frac{5}{2^{2}}+\frac{7}{2^{3}}+\cdots +\frac{2n-1}{2^{p-1}}+\frac{2n+1}{z^{\theta }},}$<br/>${\frac{S_{n}}{2}=\frac{3}{2^{2}}+\frac{5}{2^{3}}+\frac{7}{2^{4}}+\cdots +\frac{2n-1}{2^{n}}+\frac{2n+1}{2^{n}+1},}$<br/>①-②,得${\frac{S_{e}}{z}=\frac{3}{z}+}${+\frac{7}{2^{3}}+\cdots +\frac{1}{2^{s}}}${=\frac{3}{2}+}${z^{e}+x^{2}}$ ${1-\frac{7}{2}}$<br/>${=\frac{5}{x}-\frac{2n+5}{a+1},}$<br/>所以${S_{n}=5-\frac{2n+5}{2^{n}}}$12分<br/>21.(I)在△ABD中,∵${\cos \angle ADB=\frac{3}{5},\therefore \sin \angle ADB=\frac{4}{5}.}$<br/>sin∠CAD=sin(∠ADB-${\angle AcD,=\sin \angle ADB\cos \frac{\pi}{4}-\cos \angle ADB\sin \frac{\pi}{4}}$<br/>${=\frac{4}{5}\times \frac{\sqrt {2}}{2}-\frac{3}{5}\times \frac{\sqrt {2}}{2}=\frac{\sqrt {2}}{10}}$<br/>在△ADC中,由正弦定理得${\frac{Ac}{\sin \angle ADc}=\frac{cD}{\sin \angle CAD}=\frac{AD}{\sin \angle ACD}}${\frac{AC}{\frac{4}{5}}=\frac{cD}{\sqrt {2}}=\frac{5\sqrt {2}}{\sqrt {2}}}$<br/>解得${AC=8,CD=\sqrt {2},}$<br/>${\Pi)\because \overrightarrow {CA}\cdot \overrightarrow {CB}=48,}${8\cdot cB\cdot \frac{\sqrt {2}}{2}=48.}$解得${c_{B}=6\sqrt {2},}$∴BD=CB-CD=5√2<br/>在△ABC中,A${B=\sqrt {8^{2}+(6\sqrt {2})-2\times 8\times 6\sqrt {2}}=2\sqrt {10}}$，在△ABD中<br/>${\infty \angle BAD=\frac{(2\sqrt {10})^{2}+(5\sqrt {2})}{2\times 2\sqrt {10}\times 5\sqrt {2}}=\frac{\sqrt {5}}{5}}$<br/>22.(1)由${\sin ^{2}=5}=S_{n}-5_{5}}&{T_{6}^{z}=-7}}${s_{w}^{2}=(S_{w}-S_{6-1})(s_{w}-\frac{1}{2})=s_{e}^{\vec {x}}-\frac{1}{2}S_{\varphi }-S_{6}=+\frac{7}{2}s}$<br/>${\therefore \frac{1}{s_{n}}-\frac{1}{S_{n-1}}=2(n\supseteq 2)}$<br/>${\therefore \left\lbrace \begin{array}{l}{\frac{1}{s}\rbrace }$是以${\frac{1}{s_{7}}}$为首项,以2为公差的等差数列，<br/>${\therefore \frac{1}{s_{n}}=2n-1,}$<br/>${s_{n}=\frac{1}{2n-1}(n\∈N^{*}.}$<br/>${a_{n}=\left\lbrace \begin{array}{l}{7,n=7}\\{\frac{1}{2p-1}-\frac{7}{2n-3},n\geq }\end{array}\right.}$<br/>(3)${b_{n}=\frac{7}{(2n-7)(2n+i)}=}$<br/>${\therefore 7_{8}=\frac{1}{2}(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{2\pi-1}-\frac{1}{2\pi+1})=\frac{1}{2}(-\frac{1}{2n+1})=\frac{\pi}{2\pi}}$12/'
    # svg_data = {'svg_html_data': ['<div data-v-66982a76=""><div data-v-66982a76="" class="stem-wraper"><span data-v-66982a76="" class="topic-number">1.</span><span data-v-66982a76="" class="stem">在数列<span class="MathJax_Preview" style="color: inherit; display: none;"></span><span class="MathJax_SVG" id="MathJax-Element-121-Frame" tabindex="0" data-mathml="<math xmlns=&quot;http://www.w3.org/1998/Math/MathML&quot;><mrow class=&quot;MJX-TeXAtom-ORD&quot;><mo fence=&quot;false&quot; stretchy=&quot;false&quot;>{</mo><msub><mi>a</mi><mrow class=&quot;MJX-TeXAtom-ORD&quot;><mi>n</mi></mrow></msub><mo fence=&quot;false&quot; stretchy=&quot;false&quot;>}</mo></mrow></math>" role="presentation" style="font-size: 100%; display: inline-block; position: relative;"><svg xmlns:xlink="http://www.w3.org/1999/xlink" width="4.773ex" height="2.66ex" viewBox="0 -832 2055.1 1145.2" role="img" focusable="false" style="vertical-align: -0.728ex;" aria-hidden="true"><g stroke="currentColor" 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class=&quot;MJX-TeXAtom-ORD&quot;><msub><mi>a</mi><mrow class=&quot;MJX-TeXAtom-ORD&quot;><mn>1</mn></mrow></msub><mo>=</mo><mn>1</mn><mo>,</mo><msub><mi>a</mi><mrow class=&quot;MJX-TeXAtom-ORD&quot;><mi>n</mi></mrow></msub><mo>&amp;#x2212;</mo><msub><mi>a</mi><mrow class=&quot;MJX-TeXAtom-ORD&quot;><mi>n</mi><mo>&amp;#x2212;</mo><mn>1</mn></mrow></msub><mo>=</mo><mi>n</mi><mo stretchy=&quot;false&quot;>(</mo><mi>n</mi><mo>&amp;#x2265;</mo><mn>2</mn><mo stretchy=&quot;false&quot;>)</mo><mo>,</mo></mrow></math>" role="presentation" style="font-size: 100%; display: inline-block; position: relative;"><svg xmlns:xlink="http://www.w3.org/1999/xlink" width="30.021ex" height="2.66ex" viewBox="0 -832 12925.8 1145.2" role="img" focusable="false" style="vertical-align: -0.728ex;" aria-hidden="true"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="matrix(1 0 0 -1 0 0)"><use xlink:href="#MJMATHI-61" x="0" y="0"></use><use transform="scale(0.707)" xlink:href="#MJMAIN-31" x="748" y="-213"></use><use xlink:href="#MJMAIN-3D" x="1261" y="0"></use><use xlink:href="#MJMAIN-31" x="2317" y="0"></use><use xlink:href="#MJMAIN-2C" x="2817" y="0"></use><g transform="translate(3263,0)"><use xlink:href="#MJMATHI-61" x="0" y="0"></use><use transform="scale(0.707)" xlink:href="#MJMATHI-6E" x="748" y="-213"></use></g><use xlink:href="#MJMAIN-2212" x="4539" y="0"></use><g transform="translate(5540,0)"><use xlink:href="#MJMATHI-61" x="0" y="0"></use><g transform="translate(529,-150)"><use transform="scale(0.707)" xlink:href="#MJMATHI-6E" x="0" y="0"></use><use transform="scale(0.707)" xlink:href="#MJMAIN-2212" x="600" y="0"></use><use transform="scale(0.707)" xlink:href="#MJMAIN-31" x="1379" y="0"></use></g></g><use xlink:href="#MJMAIN-3D" x="7776" y="0"></use><use xlink:href="#MJMATHI-6E" x="8832" y="0"></use><use xlink:href="#MJMAIN-28" x="9433" y="0"></use><use xlink:href="#MJMATHI-6E" x="9822" y="0"></use><use xlink:href="#MJMAIN-2265" x="10701" y="0"></use><use xlink:href="#MJMAIN-32" x="11757" y="0"></use><use xlink:href="#MJMAIN-29" x="12257" y="0"></use><use xlink:href="#MJMAIN-2C" x="12647" y="0"></use></g></svg><span class="MJX_Assistive_MathML" role="presentation"><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow class="MJX-TeXAtom-ORD"><msub><mi>a</mi><mrow class="MJX-TeXAtom-ORD"><mn>1</mn></mrow></msub><mo>=</mo><mn>1</mn><mo>,</mo><msub><mi>a</mi><mrow class="MJX-TeXAtom-ORD"><mi>n</mi></mrow></msub><mo>−</mo><msub><mi>a</mi><mrow class="MJX-TeXAtom-ORD"><mi>n</mi><mo>−</mo><mn>1</mn></mrow></msub><mo>=</mo><mi>n</mi><mo stretchy="false">(</mo><mi>n</mi><mo>≥</mo><mn>2</mn><mo stretchy="false">)</mo><mo>,</mo></mrow></math></span></span><script type="math/tex" id="MathJax-Element-122">{a_{1}=1,a_{n}-a_{n-1}=n(n\\geq 2),}</script>则该数列的通项<span class="MathJax_Preview" style="color: inherit; display: none;"></span><span class="MathJax_SVG" id="MathJax-Element-123-Frame" tabindex="0" data-mathml="<math xmlns=&quot;http://www.w3.org/1998/Math/MathML&quot;><mrow class=&quot;MJX-TeXAtom-ORD&quot;><msub><mi>a</mi><mrow class=&quot;MJX-TeXAtom-ORD&quot;><mi>n</mi></mrow></msub><mo>=</mo></mrow></math>" role="presentation" style="font-size: 100%; display: inline-block; position: relative;"><svg xmlns:xlink="http://www.w3.org/1999/xlink" width="4.902ex" height="1.817ex" viewBox="0 -520.7 2110.4 782.1" role="img" focusable="false" style="vertical-align: -0.607ex;" aria-hidden="true"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="matrix(1 0 0 -1 0 0)"><use xlink:href="#MJMATHI-61" x="0" y="0"></use><use transform="scale(0.707)" xlink:href="#MJMATHI-6E" x="748" y="-213"></use><use xlink:href="#MJMAIN-3D" x="1331" y="0"></use></g></svg><span class="MJX_Assistive_MathML" role="presentation"><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow class="MJX-TeXAtom-ORD"><msub><mi>a</mi><mrow class="MJX-TeXAtom-ORD"><mi>n</mi></mrow></msub><mo>=</mo></mrow></math></span></span><script type="math/tex" id="MathJax-Element-123">{a_{n}=}</script></span></div><!----><div data-v-66982a76="" class="topic-analysis"><ul data-v-66982a76="" class="topic-analysis-items"><li data-v-66982a76="" class="topic-analysis-content"><span data-v-66982a76="" class="analysis-prefix">【答案】</span><span data-v-66982a76=""><span class="MathJax_Preview" style="color: inherit; display: none;"></span><span class="MathJax_SVG" id="MathJax-Element-124-Frame" tabindex="0" data-mathml="<math xmlns=&quot;http://www.w3.org/1998/Math/MathML&quot;><mfrac><mn>1</mn><mn>2</mn></mfrac></math>" role="presentation" style="font-size: 100%; display: inline-block; position: relative;"><svg xmlns:xlink="http://www.w3.org/1999/xlink" width="1.658ex" height="3.262ex" viewBox="0 -935.7 713.9 1404.6" role="img" focusable="false" style="vertical-align: -1.089ex;" aria-hidden="true"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="matrix(1 0 0 -1 0 0)"><g transform="translate(120,0)"><rect stroke="none" width="473" height="60" x="0" y="220"></rect><use transform="scale(0.707)" xlink:href="#MJMAIN-31" x="84" y="576"></use><use transform="scale(0.707)" xlink:href="#MJMAIN-32" x="84" y="-536"></use></g></g></svg><span class="MJX_Assistive_MathML" role="presentation"><math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>1</mn><mn>2</mn></mfrac></math></span></span><script type="math/tex" id="MathJax-Element-124"> \\frac{1}{2} </script> \n </span></li><li data-v-66982a76="" class="topic-analysis-content"><span data-v-66982a76="" class="analysis-prefix">【解析】</span><span data-v-66982a76="">略 \n \n </span></li></ul></div></div><!----><div data-v-66982a76="" class="handle-stem" style="display: none;"><div data-v-66982a76="" class="divider" style="width: 100%; height: 1px; background-color: rgb(220, 223, 230); margin: 5px 0px;"></div><div data-v-66982a76="" class="btns" style="display: 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    #
    # wordid = "5fc0d256407550d0b7d9a43c"
    #
    # res=Ruku(items_list, ocr_html, svg_data, wordid).upload_img()
    # pprint(res)

    f1 = open(r"F:\zwj\Text_Structure\new_tiku_structure_v3_sci\struct_items.pickle",'rb').read()
    items_list = pickle.loads(f1)
    # pprint(items_list)
    f2 = open(r"F:\zwj\Text_Structure\new_tiku_structure_v3_sci\svg_data.pickle", 'rb').read()
    svg_data = pickle.loads(f2)
    # svg_data = {"svg_path": "", "svg_html_data": ""}
    htmlt = open(r"F:\zwj\Text_Structure\accept_files\624802d612cd45a7836f342e.html", "r", encoding="utf8").read()
    res = Ruku(items_list, htmlt, svg_data, "20220408", {"callback_url": "1223", "source": ""}, "高中物理").upload_img()